All categories

3 years ago

Resolver el problema

Mathematics

1 answer:

GenaCL600 [577]3 years ago

5 0

Answer: 20

Step-by-step explanation:

50 over 1 times 2 over 5 which equals 100 over 5. Divide both numbers by 5 which equals 20.

You might be interested in

Which of the following values satisfy the inequality shown? you must select all that apply -4≤20

OLEGan [10]

It’s basically the same thing as -4=20 so your answer would be -5 or D

3 0

3 years ago

Read 2 more answers

What is the solution to this system of linear equations? y − 4x = 7 2y + 4x = 2 (3, 1) (1, 3) (3, −1) (−1, 3)

ohaa [14]

Y - 4x = 7...y = 4x + 7
now sub 4x + 7 in for y in the other equation
2y + 4x = 2
2(4x + 7) + 4x = 2
8x + 14 + 4x = 2
12x = 2 - 14
12x = - 12
x = -1

y - 4x = 7
y - 4(-1) = 7
y + 4 = 7
y = 7 - 4
y = 3

solution is : (-1,3)

7 0

4 years ago

Read 2 more answers

54.628 rouned to rhe nearst tenth

likoan [24]

Round down to 54.6 because it is 5 or less.

8 0

3 years ago

Read 2 more answers

Consider the function below. (If an answer does not exist, enter DNE.) g(x) = 190 + 8x3 + x4 (a) Find the interval of increase.

galben [10]

Answer:

The interval of increase of g(x) is $(-6,+\infty)$ .

Step-by-step explanation:

The interval of increase occurs when first derivative of given function brings positive values. Let be $g(x) = 190 + 8 \cdot x^{3} + x^{4}$ , the first derivative of the function is:

$g'(x) = 24 \cdot x ^{2} + 4\cdot x^{3}$

$g'(x) = 4 \cdot x^{2}\cdot (6+x)$

The following condition must be met to define the interval of increase:

$4\cdot x^{2} \cdot (x+6) > 0$

The first term is always position due to the quadratic form, the second one is a first order polynomial and it is known that positive value is a product of two positive or negative values. Then, the second form must satisfy this:

$x + 6 > 0$

The solution to this inequation is:

$x > - 6$

Now, the solution to this expression in interval notation is: $(-6,+\infty)$

3 0

3 years ago

CAN YOU PLEASE HELP ASAP!?

MAVERICK [17]

Apples went up 0.75 a lb

p is the start price so new price is p + 0.75

we buy 3 lbs

3 ( p+ 0.75) = 5.88

now solve

3p + 2.25 = 5.88

-2.25 -2.25

3p = 3.63

/3 /3

p = 1.21 a lb

4 0

3 years ago

Read 2 more answers