The first one is fair and the second one is fair as well
Answer:
42.22% probability that the weight is between 31 and 35 pounds
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean and standard deviation , the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:
What is the probability that the weight is between 31 and 35 pounds
This is the pvalue of Z when X = 35 subtracted by the pvalue of Z when X = 31. So
X = 35
has a pvalue of 0.5557
X = 31
has a pvalue of 0.1335
0.5557 - 0.1335 = 0.4222
42.22% probability that the weight is between 31 and 35 pounds
Domain- {-2, 1, 0, 1, 2}
Range- {-2, 0, 2}
My domain is right but I don’t think my range is. I did learn this 4 years ago though so
Answer:
g
Step-by-step explanation:
Answer/Step-by-step explanation:
8. m<DEF = 122°
m<FEG + m<DEF = 180° (Angles on a straight line)
m<FEG + 122 = 180 (Substitution)
m<FEG = 180 - 122
m<FEG = 58°
9. m<BOC = 27°
m<AOC = 47°
m<AOB + m<BOC = m<AOC (angle addition postulate)
m<AOB + 27 = 47 (substitution)
m<AOB = 47 - 27 (Subtraction property of equality)
m<AOB = 20°