Complete question :
The temperature at 5:00 a.m. was –6 °F. By 3:00 p.m., the temperature had risen to a high of 36 °F. If the temperature at 8:00 p.m. decreased from the high by the change in temperature in Fahrenheit degrees from 5:00 a.m. to 3:00 p.m., what was the temperature at 8:00 p.m.?
Answer:
-6°F
Step-by-step explanation:
Temperature at 5am (t1) = - 6°F
Temperature at 3pm (t2) = 36°F
Change in temperature, between 5am and 3pm:
(t2 - t1) = (36 - (-6)) = (36 + 6) = 42°F
Hence, temperature at 8:00 pm:
High temperature - change in temperature between (5am - 3pm)
36°F - 42°F = - 6°F
Answer: 5m + 20 miles
Step-by-step explanation:
Miles driven on first day = m
On the second day, they drive five more miles than they did on the first day. This will be: = m + 5
On the third day, they drove three times as many miles as they did on the second day. This will be:
= 3(m + 5)
= 3m + 15
Total miles driven will now be:
= m + m+5 + 3m + 15
= 5m + 20
The answer is 50
The ratio of boys to girls is 10:25 in the school
If sample has 20 boys (10x2) then based on ratio it would likely have 50 girls (25x2)
The domain would be D. The number of minutes the student studied.
Step-by-step explanation:
The red line in the graph above measures the median home price, and this is often a better "average" for us to be used with home prices and home values. Unfortunately, it is not as easy to calculate and it does not work well with tiny data sets, so we often only see it used with very large data sets (like whole Cities, States, etc.) produced by the large real estate aggregators. Additionally, not many real estate agents know how to generate them for neighborhoods or zip codes (but we can at the Tallahassee Real Estate Blog :)).
