Question

Pls help me with trig i would rlly appreciate !! 22 only

Answer 1

Step-by-step explanation:

given,

tan thita =8/9

or,tan thita=p/b

now, h=

$\sqrt{p {}^{2} + b {}^{2} }$

$= \sqrt{8 {}^{2} + 9 {}^{2} }$

$= \sqrt{145}$

therefore, h=

$\sqrt{145}$

now, cos thita =b/h

so, cos thita =

$9 \div \sqrt{145}$

$= 9 \sqrt{145} \div \sqrt{145}$

......ans........

hope its helpful

Answer 2

I think none of these answers are correct