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My name is Ann [436]
3 years ago
7

Complete the pattern? AC BD CE DF ___

Mathematics
2 answers:
Vesna [10]3 years ago
8 0
The next one would be EG
pogonyaev3 years ago
6 0

Answer:

AC BD CE DF EG FH GI

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What is the product of <br>(7/8)(-16)(-7)(-1/14)<br><br>A -7<br>B -9/16<br>C -1/7<br>D 23/12​
Nat2105 [25]

Answer:

-7

Step-by-step explanation:

(7/8)(-16)(-7)(-1/4)

(7/8)(-1/4)(-16)(-7)

(-1/16)(112)

-7

4 0
3 years ago
The distribution of the amount of money spent by students on textbooks in a semester is approximately normal in shape with a mea
zheka24 [161]

Answer:

$301 - $397

Step-by-step explanation:

Using the Empirical rule

1) 68% of data falls within 1 standard deviation from the mean - that means between μ - σ and μ + σ .

2)95% of data falls within 2 standard deviations from the mean - between μ – 2σ and μ + 2σ .

3)99.7% of data falls within 3 standard deviations from the mean - between μ - 3σ and μ + 3σ .

From the above question,

Mean = 349 , standard deviation = 24.

Confidence interval = 95%

Using 2)95% of data falls within 2 standard deviations from the mean - between μ – 2σ and μ + 2σ .

μ – 2σ

= 349 - 2(24)

= 349 - 48

= 301

μ + 2σ

349 + 2(24)

= 349 + 48

= 397

Therefore, according to the standard deviation rule, approximately 95% of the students spent between $301 and $397 on textbooks in a semester.

8 0
3 years ago
Sketch the graph of each line
sveta [45]
Use Desmos it helps you with questions like that

3 0
2 years ago
Use the drawing tool(s) to form the correct answer on the provided coordinate plane.
vlada-n [284]

Answer:

Step-by-step explanation:

X^2-6x+5=x^2-5x-x+5=x(x-5)-(x-5)=(x-5)(x-1)

Then we have (x-5)(x-1)=0 if x=5 or x=1.

Intersections on x are points (1,0) and (5,0), middle is (3,0).

Intersection with y is when put x=0 in equation, so you will get y=0-6*0+5, y=5. The point is (0,5).

From picture symmetry is line x=3.

7 0
3 years ago
PLEASE HELP! Screenshot attached
nadya68 [22]

Answer:

( x - 6 ) ( x - 3 ) (x + 4)

Step-by-step explanation:


6 0
3 years ago
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