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iris [78.8K]
3 years ago
11

30 points on this question simply find the volumes of tank a and then find the volume of tank b.

Mathematics
2 answers:
maksim [4K]3 years ago
7 0

Answer:

volume of tank a=65.63

volume of tank b=61.88

Step-by-step explanation:

3.5*3.75*5=65.63

3*3.75*5.5=61.88

brainliest plz

ivolga24 [154]3 years ago
6 0

Answer:

Tank A: 65.625

Tank B: 61.875

Step-by-step explanation:

For tank a you do: 5x3 3/4x3 1/2

For tank b you do: 5 1/2x3 3/4x3

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Gary deposits $1,500 into each of two savings accounts. Account I earns 5% annual simple interest. Account II earns 5% interest
hodyreva [135]

Answer:

  • $3623.26

Step-by-step explanation:

<u>Given</u>

  • Each deposit = $1500
  • Interest rate= 5%
  • Time = 4 years
  • Compound number = annual

<u>Simple interest account</u>

  • B = 1500*(1 + 4*0.05) = 1500*1.2 = $1800

<u>Compound interest account</u>

  • B = 1500*(1 + 0.05)^4 = $1823.26

<u>Total balance</u>

  • $1800 + $1823.26 = $3623.26

7 0
3 years ago
PLEASE HELP!!! 40 points!!! 1) A school puts on a play. The play costs $1,200.00 in expenses. The students charge $4.00 for tick
Xelga [282]
Since it costs 1200, we subtract 1200 from the start. In addition, the money totaled is 4*x, where x is the amount of tickets sold. Since there are a minimum of 0 tickets able to be sold and a maximum of 500 tickets since there are 500 seats, the answer is D
8 0
3 years ago
The nth term of a sequence is n + 5<br> Work out the 5th term of the sequence.<br> 5th term =
Ilya [14]

Answer:

10

Step-by-step explanation:

Tₙ=n+5

T₅=5+5=10

4 0
3 years ago
A tire manufacturer warranties its tires to last at least 20,000 miles orâ "you get a new set ofâ tires." In itsâ experience, a
Y_Kistochka [10]

Answer:

Probability that a set of tires wears out before 20,000 miles is 0.1151.

Step-by-step explanation:

We are given that a tire manufacturer warranties its tires to last at least 20,000 miles or "you get a new set of tires." In its past experience, a set of these tires last on average 26,000 miles with S.D. 5,000 miles. Assume that the wear is normally distributed.

<em>Let X = wearing of tires</em>

So, X ~ N(\mu=26,000,\sigma^{2}=5,000^{2})

Now, the z score probability distribution is given by;

         Z = \frac{X-\mu}{\sigma} ~ N(0,1)

where, \mu = average lasting of tires = 26,000 miles

            \sigma = standard deviation = 5,000 miles

So, probability that a set of tires wears out before 20,000 miles is given by = P(X < 20,000 miles)

    P(X < 20,000) = P( \frac{X-\mu}{\sigma} < \frac{20,000-26,000}{5,000} ) = P(Z < -1.2) = 1 - P(Z \leq 1.2)

                                                                    = 1 - 0.88493 = 0.1151

Therefore, probability that a set of tires wears out before 20,000 miles is 0.1151.

4 0
3 years ago
What is 4.5 times 10 to the third power?
seropon [69]
4500 is the answer to this question.
8 0
3 years ago
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