Answer:
9
Step-by-step explanation:
First, find <em>x</em>. Since <em>x</em> is the average of the three number, add the three up and then divided by three. Thus:
![x=\frac{13+-16+6}{3}=3/3=1](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B13%2B-16%2B6%7D%7B3%7D%3D3%2F3%3D1)
<em>y</em> is the cube root of 8. Thus:
![y=\sqrt[3]{8}=2](https://tex.z-dn.net/?f=y%3D%5Csqrt%5B3%5D%7B8%7D%3D2)
So:
![x^2+y^3\\=(1)^2+(2)^3\\=1+8=9](https://tex.z-dn.net/?f=x%5E2%2By%5E3%5C%5C%3D%281%29%5E2%2B%282%29%5E3%5C%5C%3D1%2B8%3D9)
It must be 6 since the length sides r doubled and it's similar
Answer:
1. graph, horizontal, vertical
2. closer
3. left, right
4. positive, negative
I've been trying to find a graph maker so I can plot the numbers... but I can't find one.
edit: I attached a (x,y) graph just so you can see where the positive and negative numbers are. just so you can visualize it.