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Neporo4naja [7]
3 years ago
15

Albuterol is used to calm bronchospasm. It has a biological half-life of 7 hours and is normally inhaled as a 1.25 mg dose. (Not

e: Use the concepts of half-life or doubling time. The biological half-life of a substance is the amount of time it takes for the physiologic or radiologic activity of that substance to reduce by half.)
Required:
a. Find a model for the amount of albuterol left in the body t hours after an initial dose of 1.25 mg.
b. How much albuterol is left in the body after 24 hours?
Mathematics
1 answer:
nika2105 [10]3 years ago
3 0

Answer:

a. N(t) = 1.25 (1/2)^t/7

b. 0.1160933038mg.

Step-by-step explanation:

The formula for half life =

N(t) = No(1/2)^t/t½

Where N(t) = Amount of Substance left

No = Initial amount not Substance

t = time after t years

t½ = Half life of the substance

From the question:

No = 1.25mg

t½ = 7 years

a. Find a model for the amount of albuterol left in the body t hours after an initial dose of 1.25 mg.

N(t) = No(1/2)^t/t½

No = 1.25mg

t½ = 7 years

N(t) = 1.25 (1/2)^t/7

b. How much albuterol is left in the body after 24 hours?

Using the model in the above question

N(t) = 1.25 (1/2)^t/7

N(t) = 1.25(1/2)^24/7

N(t) = 1.25(0.5)^3.4285714286

N(t) = 0.1160933038mg

Therefore, the quantity of albuterol left in the body after 24 hours is 0.1160933038mg.

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Part 1) It is not possible to apply the Pythagorean Theorem to find the missing side, because is not a right triangle

Part 2) I would use the law of the cosine, because to apply the law of sine I would need to know the value of angle C or angle B

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Part 5) The measure of angle B is 88\°

Step-by-step explanation:

Part 1) Can you use Pythagorean Theorem to find the missing side?

we know that

The Pythagorean Theorem is used in a right triangle

The triangle ABC of the figure is not a right triangle

therefore

It is not possible to apply the Pythagorean Theorem to find the missing side

Part 2) Would you use Law of Sine or Law of Cosine to find the length of side CB?    

I would use the law of the cosine, because to apply the law of sine I would need to know the value of angle C or angle B

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BC^{2}=AB^{2}+AC^{2}-2(AB)(AC)cos(A)

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BC^{2}=255^{2}+440^{2}-2(255)(440)cos(57\°)

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Part 4) Find the measure of angle C. (Hint: use the other “Law”). Round your answer to the nearest whole degree

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\frac{AB}{sin(C)}=\frac{CB}{sin(A)}

substitute the values

\frac{255}{sin(C)}=\frac{369}{sin(57\°)}

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C=arcsin(0.5796)=35\°

Part 5) What is the measure of angle B? Show your work and round your answer to the nearest whole degree.

Remember that

the sum of the interior angles of a triangle must be equal to 180 degrees

sp

substitute the values and solve for <B

57\°+

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