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wariber [46]
3 years ago
14

PLZ HELP ASAP!!! Ben uses a compass and a straightedge to construct ∠DEF ≅ ∠ABC, as shown below:

Mathematics
1 answer:
Mariulka [41]3 years ago
4 0

Answer:

  • ∠DEF ≅ ∠ABC when BH = EJ, BI = EK, and HI = JK

Step-by-step explanation:

<u>Corresponding segments are:</u>

  • BH and ED, BI and EK, HI and JK

Therefore last option is correct

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Work shown below!

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lilavasa [31]

Answer:

g(n-7)=\frac{n^{2}-14n+43}{7n-49}  → (a)

Step-by-step explanation:

We need to evaluate g(n - 7), where

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Replace x by (n - 7) to evaluate it

∵ x = (n - 7)

∴ g(n-7)=\frac{(n-7)^{2}-6}{7(n-7)}

→ Let us find (n - 7)²

∵ (n - 7)² = (n - 7)(n - 7) = (n)(n) + (n)(-7) + (-7)(n) + (-7)(-7)

∴ (n - 7)² = n² + (-7n) + (-7n) + 49 = n² + -14n + 49

∴ (n - 7)² = n² - 14n + 49

→ Find 7(n - 7)

∵ 7(n - 7) = 7(n) - 7(7)

∴ 7(n - 7) = 7n - 49

→ Now let us write then in the form above

∵ g(n-7)=\frac{n^{2}-14n+49-6}{7n-49}

→ Add the like terms in the numerator

∴  g(n-7)=\frac{n^{2}-14n+43}{7n-49}

The correct answer is (a)

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Step-by-step explanation:

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