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Elina [12.6K]
3 years ago
6

What is the slope of a line perpendicular to the line x/2 − y/3 =1?

Mathematics
1 answer:
Anestetic [448]3 years ago
8 0
The product of the slope of perpendicular lines is always -1
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For an angle θ with the point (−5, −12) on its terminating side, what is the value of cosine?
viva [34]

Answer:

option C. -\frac{5}{13}

Step-by-step explanation:

we have  that

The point (-5,-12) belong to the III quadrant

so

The value of the cosine is negative

Applying the Pythagoras Theorem

Find the value of the hypotenuse

h^{2}=5^{2}+12^{2}\\ h^{2} =25+144\\ h^{2}=169\\h=13\ units

The value of cosine of angle θ is the ratio between the side adjacent to angle θ and the hypotenuse

cos(\theta)=-\frac{5}{13}

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forsale [732]

Answer:

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Step-by-step explanation:

Given parameters:

  Equation of the line ;

           y  = -5x + 1

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Solution:

A line perpendicular to  y  = -5x + 1  will have slope that is a negative inverse of the given one.

Equation of a straight line is expressed as;

           y  = mx + c

y and x are the coordinates

m is the slope

c is the y-intercept

        So, the slope of the new line perpendicular is \frac{1}{5} ;

Now let us find the y-intercept of the new line;

   x = -1 and y = 2

      2  = \frac{1}{5} x (-1) + c

           c  = 2 + \frac{1}{5}   = \frac{11}{5}  

The equation of the new line is;

          y  =  \frac{1}{5}x +  \frac{11}{5}  

or multiply through by 5;

        5y  = x + 11

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A

Step-by-step explanation:

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