Question

In a​ survey, 36​% of the respondents stated that they talk to their pets on the telephone. A veterinarian believed this result to be too​ high, so she randomly selected 240 pet owners and discovered that 79 of them spoke to their pet on the telephone. Does the veterinarian have a right to be​ skeptical? Use the alphaequals0.05 level of significance.Use technology to find the P-value.P-value=???(Round to three decimal places as needed.)

Answer 1

Answer: p value is 0.1685.

Step-by-step explanation:

Since we have given that

The survey is conducted on a random sample of 240 pet owners.

Out of them, number of owners spoke to their pet on telephone = 79

n = 240

x = 79

$\hat{p}=\dfrac{x}{n}=\dfrac{79}{240}=0.33$

Our hypothesis would be

$H_0:p=0.5\\\\H_1:p>0.5$

Formula for test statistic would be

$\dfrac{\hat{p}-p}{\sqrt{\dfrac{p(1-p)}{n}}}\\\\=\dfrac{0.33-0.36}{\sqrt{\dfrac{0.36(1-0.36)}{240}}}\\\\=-0.96$

p value = 0.1685

Hence, p value is 0.1685.