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Alexeev081 [22]
4 years ago
8

If the Williams family has a monthly income of $3000 how much do they spend on clothing and entertainment

Mathematics
1 answer:
MA_775_DIABLO [31]4 years ago
5 0
$360

To solve this, multiply 3000 by 12%.

3000 x 12%

To convert percentages to decimals, divide them by 100 and remove the % sign.
So... 12% = 0.12

= 3000 x 0.12
= 360
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After sitting in a refrigerator for a while, a turkey at a temperature of 34 degrees F is placed on the counter and slowly warms
Anton [14]

Answer:

  • k = 0.006
  • T = 48 °F

Step-by-step explanation:

The initial temperature difference of 72 -34 = 38 °F is reduced to a difference of 72 -41 = 31 °F after 35 minutes. The exponential term in the temperature expression could have the factor ...

  (31/38)^(t/35) = e^(-kt)

Taking the natural log, we find ...

  (t/35)ln(31/38) = -kt

  k = ln(38/31)/35 ≈ 0.00581711

To the nearest thousandth, this is ...

  k ≈ 0.006

Using this in the equation for temperature, we have ...

  T = 72 -38e^(-0.006t)

Filling in the desired value for t (80), we find the turkey temperature after 80 minutes to be about

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The value of k is about 0.006, and the turkey temperature is about 48 °F.

4 0
3 years ago
A quality analyst wants to construct a control chart for determining whether four machines, all producing the same product, are
netineya [11]

Answer:

Step-by-step explanation:

1) As the sample size is 1,000 and there are 23 defectives in the output of the sample collected from Machine #1, the answer is 23/1000=0.023.

2) Estimate of the process proportion of defectives is the average of the proportion of defectives from all samples. In this case, it is : (23+15+29+13)/{4*(1000)}=80/4000=0.02.

3) Estimate of the Standard Deviation: Let us denote the mean (average) of the proportion of defectives by p. Then, the estimate for the standard deviation is : sqrt{p*(1 - p)/n}. Where n is the sample size. Putting p = 0.02, and n = 1000, we get: σ=0.0044.

4) The control Limits for this case, at Alpha risk of 0.05 (i.e. equivalent to 95% confidence interval), can be found out using the formulas given below:

Lower Control Limit : p - (1.96)*σ = 0.02 - (1.96)*0.0044=0.0113.

& Upper Control Limit: p + (1.96)*σ = 0.02 + (1.96)*0.0044 = 0.0287.

5) The proportion defective in each case is : Machine #1: 0.023; Machine #2: 0.015; Machine# 3: 0.029; Machine# 4: 0.013. For the Lower & Upper control limits of 0.014 & 0.026; It is easy to see that Machines #3 & #4 appear to be out of control.

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