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3 years ago

Jayne uses long division to convert a rational number ab to a decimal. Which of the following statements cannot be true?

Mathematics

1 answer:

solmaris [256]3 years ago

8 0

The decimal form of ab eventually repeats.

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kvv77 [185]

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4 0

3 years ago

Find the smallest positive integer solution to the following system of congruences: x = 0 (mod 5) x = 8 (mod 11) The solution is

igomit [66]

Answer:

The smallest positive integer solution to the given system of congruences is 30.

Step-by-step explanation:

The given system of congruences is

$x=0(mod5)$

$x=8(mod11)$

where, m and n are positive integers.

It means, if the number divided by 5, then remainder is 0 and if the same number is divided by 11, then the remainder is 8. It can be defined as

$x=5m$

$x=11n+8$

$5m\cong 11n+8$

Now, we can say that m>n because m and n are positive integers.

For n=1,

$5m=11(1)+8=19$

$5m=19$

19 is not divisible by 5 so m is not an integer for n=1.

For n=2,

$5m=11(2)+8$

$5m=30$

$m=6$

The value of m is 6 and the value of n is 2. So the smallest positive integer solution to the given system of congruences is

$x=5(6)=30$

Therefore the smallest positive integer solution to the given system of congruences is 30.

8 0

4 years ago

Find the distance from the start of thetrail to the end of the trail.

Bumek [7]

Where’s the rest of the question??

8 0

3 years ago

Least common multiple to 4,5,10

KATRIN_1 [288]

the answer is 20 because the lowest number they can all mulitply to is 20

8 0

3 years ago

Uma função f é dada por f(x) = ax + b, em que a e b são números reais. Se f(–1) = 3 e f(1) = –1, determine o valor de f(3).

ale4655 [162]

F(x) = ax + b
Usa-se a informacao dada para criar um sistema de 2 equacoes com 2 variaveis. Resolve-se o sistema pare determinar os valores de a e b.Uma vez que se sabe os valores de a e b, escreve-se a funcao f com os valores de a e b. Finalmente calcucla-se f(3) usando a funcao f.

f(-1) = 3

a(-1) + b = 3

f(1) = -1

a(1) + b = -1

O sistema de equacoes e o seguinte.
Resolvemo-lo par adicao.
A variavel a e eliminada.

-a + b = 3
a + b = -1

2b = 2

b = 1

a + 1 = -1

a = -2

Agora sabemos the a = -2 e b = 1.
Escrevemos a funcao f usando os valores the a e b calculados..

f(x) = -2x + 1

f(3) = -2(3) + 1 = -6 + 1 = -5

f(3) = -5

6 0

3 years ago