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Anastaziya [24]
3 years ago
6

Plz help I'm halfway through the lesson​

Mathematics
2 answers:
Inessa05 [86]3 years ago
8 0
3.5555555556/ 3rd one
Solnce55 [7]3 years ago
5 0
3.5555555556 / the third one
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Determine what type of model best fits the given situation:
lyudmila [28]

Let value intially be = P

Then it is decreased by 20 %.

So 20% of P = \frac{20}{100} \times P = 0.2P

So after 1 year value is decreased by 0.2P

so value after 1 year will be = P - 0.2P (as its decreased so we will subtract 0.2P from original value P) = 0.8P-------------------------------------(1)

Similarly for 2nd year, this value 0.8P will again be decreased by 20 %

so 20% of 0.8P = \frac{20}{100} \times 0.8P = (0.2)(0.8P)

So after 2 years value is decreased by (0.2)(0.8P)

so value after 2 years will be = 0.8P - 0.2(0.8P)

taking 0.8P common out we get 0.8P(1-0.2)

= 0.8P(0.8)

=P(0.8)^{2}-------------------------(2)

Similarly after 3 years, this value P(0.8)^{2} will again be decreased by 20 %

so 20% of P(0.8)^{2}  \frac{20}{100} \times P(0.8)^{2} = (0.2)P(0.8)^{2}

So after 3 years value is decreased by (0.2)P(0.8)^{2}

so value after 3 years will be = P(0.8)^{2}   - (0.2)P(0.8)^{2}

taking P(0.8)^{2} common out we get P(0.8)^{2}(1-0.2)

P(0.8)^{2}(0.8)

P(0.8)^{3}-----------------------(3)

so from (1), (2), (3) we can see the following pattern

value after 1 year is P(0.8) or P(0.8)^{1}

value after 2 years is P(0.8)^{2}

value after 3 years is P(0.8)^{3}

so value after x years will be P(0.8)^{x} ( whatever is the year, that is raised to power on 0.8)

So function is best described by exponential model

y = P(0.8)^{x} where y is the value after x years

so thats the final answer

3 0
3 years ago
Find the value of the expression w^3 if w= 7=
Tasya [4]
Answer
Substitute w by 7
7^3
7x7x7 =343
3 0
2 years ago
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Please answer 7/10k=21 find x ill give you brainliest
algol [13]

Answer:

k=2.1

Step-by-step explanation:

7/10k=21

x7         x7 Multiply seven from each side of the equation.

10k=21

/10    /10 Divide ten from each side of the equation. 21/10=2.1

k=2.1

3 0
3 years ago
The radius of Earth is 6,378.1 km, which is 18,983.9 km less than the radius of Uranus. Find the radius of Uranus.
Anton [14]
Uranus has an equatorial radius of 25,559 km and a radius of 24,973 km at the poles.
4 0
3 years ago
Allison has 4 1/2 cups of sugar. She used 2/3 of it to make cookies. How much sugar did Allison use for the cookies?
solmaris [256]
Answer:

1 1/2 cups

Work: 2/3 of 4 1/2= 3
4 1/2-3= 1 1/2
7 0
3 years ago
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