Find the logarithm. Give an approximation to four decimal places. Log 2.06

There were 56 corn dogs sold at the fair in one hour. A total of 448 tickets were collected for the corn dogs. How many tickets

Zarrin [17]

448/56 is 8 so it takes 8 tickets for one corn dog. 8 x 30 is 240
I hope that helps!

6 0

3 years ago

A national survey of 2000 adult citizens of a nation found that 24% dreaded Valentine's Day. The margin of error for the surve

Goryan [66]

Answer:

The correct option is (A).

Step-by-step explanation:

The (1 - α)% confidence interval for the population proportion is:

$CI=\hat p \pm MOE$

The information provided is:

$\hat p$ = 0.24

MOE = 0.089

The 85% confidence interval for the population proportion of adults who dreaded Valentine's Day is:

$CI=\hat p \pm MOE$

$=0.24\pm 0.089\\=(0.151, 0.329)$

So, the 85% confidence interval for the population proportion of adults who dreaded Valentine's Day is (0.151, 0.329).

The (1 - α)% confidence interval for population parameter implies that there is a (1 - α) probability that the true value of the parameter is included in the interval.

Or, the (1 - α)% confidence interval for the parameter implies that there is (1 - α)% confidence or certainty that the true parameter value is contained in the interval.

So, the 85% confidence interval for the population proportion, (0.151, 0.329), implies that there is 85% confidence that the proportion of the adult citizens of the nation that dreaded Valentine's Day is between 0.151 and 0.329.

Or there is 0.85 probability that the true proportion of the adult citizens of the nation that dreaded Valentine's Day is between 0.151 and 0.329.

Thus, the correct option is (A).

7 0

3 years ago

HELP ASAP!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

UNO [17]

Answer:

how are we supposed to help with that

Step-by-step explanation:

use your snip tool on your computer and connect them

7 0

4 years ago

Read 2 more answers

Zach's step counter tracked how many steps he took each day for a week. Number of steps 2,000 4,000 6,000 8,000 10,000 What was

swat32

The median of his steps will be five thousand

7 0

3 years ago

Assume that when adults with smartphones are randomly selected, 51% use them in meetings or classes. If 7 adult smartphone use

Morgarella [4.7K]

Answer:

$P(X \geq 3) = 1-P(X$

If we find the individual probabilities we gotL

$P(X=0)=(7C0)(0.51)^0 (1-0.51)^{7-0}=0.0068$

$P(X=1)=(7C1)(0.51)^1 (1-0.51)^{7-1}=0.0494$

$P(X=2)=(7C2)(0.51)^2 (1-0.51)^{7-2}=0.1543$

And replacing we got:

$P(X \geq 3) = 1- [0.0068 +0.0494 +0.1543]= 0.7895$

Step-by-step explanation:

Previous concepts

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".

Solution to the problem

Let X the random variable of interest, on this case we now that:

$X \sim Binom(n=7, p=0.51)$

The probability mass function for the Binomial distribution is given as:

$P(X)=(nCx)(p)^x (1-p)^{n-x}$

Where (nCx) means combinatory and it's given by this formula:

$nCx=\frac{n!}{(n-x)! x!}$

For this case we want to find this probability:

$P(X \geq 3)$

And we can use the complement rule for this case:

$P(X \geq 3) = 1-P(X$

If we find the individual probabilities we gotL

$P(X=0)=(7C0)(0.51)^0 (1-0.51)^{7-0}=0.0068$

$P(X=1)=(7C1)(0.51)^1 (1-0.51)^{7-1}=0.0494$

$P(X=2)=(7C2)(0.51)^2 (1-0.51)^{7-2}=0.1543$

And replacing we got:

$P(X \geq 3) = 1- [0.0068 +0.0494 +0.1543]= 0.7895$

7 0

3 years ago