4 years ago

How many students in all scored 100 or 95? PLEASE HELP!! And with question 2. And 3.

1 answer:

4 0

The answer for #2. 2
for # 3. 32 students

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solmaris [256]

1512 I believe! :) I would double all the dimensions first, then multiply them all together.

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3 years ago

gogolik [260]

Answer:

I think its 31

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3 years ago

photoshop1234 [79]

Answer: 8/15 + 2/5 = 0.93etc or 14/15

Step-by-step explanation:

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2 years ago

Anastasy [175]

520.8 i think i just added them!

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3 years ago

luda_lava [24]

Answer: $0.3849$

Step-by-step explanation:

Given : sample size : n= 51

sample standard deviation : s= 0.46

Significance level : $\alpha=1-0.95=0.05$

Using chi-square distribution, the critical values will be :

$\chi^2_{\alpha/2, n-1}=\chi_{0.025,\ 50}=71.4202$

$\chi^2_{1-\alpha/2, n-1}=\chi_{0.975,\ 50}=32.3574$

Confidence interval for population standard deviation ( $\sigma$ ) :

$\sqrt{\dfrac{s^2(n-1)}{\chi^2_{\alpha/2}}}$

Substitute all the values , we get

$\sqrt{\dfrac{(0.46)^2(50)}{71.4202}}$

Hence, the 95% two-sided confidence interval for σ : $0.3849$

8 0

3 years ago