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Romashka [77]
3 years ago
8

If you spin the spinner 10 times, what is the best prediction possible for the number of times it will land on blue

Mathematics
2 answers:
Alexus [3.1K]3 years ago
8 0

Answer:

It depends on how many other colors there are

Step-by-step explanation:

lyudmila [28]3 years ago
5 0

Answer:

10

Step-by-step explanation:

If you spin the spinner 11 times, what is the best prediction possible for the number of times it will land on blue?

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12r-5 61°<br> R<br> A) 790<br> C) 140°<br> B) 70°<br> D) 970
Yanka [14]

Answer:

79 because x = 7 so 12 x7 - 5 =79

5 0
2 years ago
Layla ran 4 3/8 miles on Saturday and 4 3/8 miles on Sunday. How many miles did Layla run in all on Saturday and Sunday?
soldi70 [24.7K]
4 3/8 + 4 3/8 = 8 3/4 or 8.75 miles
8 0
2 years ago
The equation is (9+6)+4=(5+ blank)+4​
rusak2 [61]
10 is your answer!! hope this helps
4 0
2 years ago
Read 2 more answers
We are interested in the amount that students study per week. Suppose you collected the following data in hours {4.4, 5.2, 6.4,
olga nikolaevna [1]

Answer:

Step-by-step explanation:

Hello!

The objective is to estimate the average time a student studies per week.

A sample of 8 students was taken and the time they spent studying in one week was recorded.

4.4, 5.2, 6.4, 6.8, 7.1, 7.3, 8.3, 8.4

n= 8

X[bar]= ∑X/n= 53.9/8= 6.7375 ≅ 6.74

S²= 1/(n-1)*[∑X²-(∑X)²/n]= 1/7*[376.75-(53.9²)/8]= 1.94

S= 1.39

Assuming that the variable "weekly time a student spends studying" has a normal distribution, since the sample is small, the statistic to use to perform the estimation is the student's t, the formula for the interval is:

X[bar] ± t_{n-1;1-\alpha /2}* (S/√n)

t_{n-1;1-\alpha /2}= t_{7;0.975}= 2.365

6.74 ± 2.365 * (1.36/√8)

[5.6;7.88]

Using a confidence level of 95% you'd expect that the average time a student spends studying per week is contained by the interval [5.6;7.88]

I hope this helps!

3 0
3 years ago
Read 2 more answers
A very large number of college men were asked what they thought their ideal weight was . A five-number summary of the responses
Sergeu [11.5K]

Answer:

50%

Step-by-step explanation:

The interval between the first quartile,25-th percentile, (155) and the third quartile, 75-th percentile, (196) comprises 50% of the sample data.

The desired interval is from 155 to 195 pounds, which starts exactly at the first quartile and ends just one pound short of the third quartile. Since this sample has a large number of men and a range of 102 pounds, that one pound difference can be neglected. Therefore, the percent of men who gave a response that falls in the interval 155 to 195 pounds can be guessed to be roughly 50%.

6 0
3 years ago
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