Answer:
you need to have the time traveled in order to get distance.
Step-by-step explanation:
d/t=s. so speed × time = distance
Answer:
the answer is 104
Step-by-step explanation:
Answer:
the a is c tthinck
Step-by-step explanation:
Step-by-step explanation:
Note: Question does not indicate if probability required is for weight to exceed or below 3000 lbs. So choose appropriate answer accordingly (near the end)
Using the usual notations and formulas,
mean, mu = 3550
standard deviation, sigma = 870
Observed value, X = 3000
We calculate
Z = (X-mu)/sigma = (3000-3550)/870 = -0.6321839
Probability of weight below 3000 lbs
= P(X<3000) = P(z<Z) = P(z<-0.6321839) = 0.2636334
Answer:
Probability that a car randomly selected is less than 3000
= P(X<3000) = 0.2636 (to 4 decimals)
Probability that a car randomly selected is greater than 3000
= 1 - P(X<3000) = 1 - 0.2636 (to 4 decimals) = 0.7364 (to 4 decimals)
Answer: Our required probability is 0.304.
Step-by-step explanation:
Since we have given that
N = 21
Number of improperly drilled holes k = 4
Number of properly drilled holes = N-k= 21-4=17
Let X be the number of improperly drilled holes in a sample of 5.
We will use "Binomial distribution":
So, our required probability is 0.304.
