The question is find the height of the tree, given that at two points 65 feet apart on the same side of the tree and in line with it, the angles of elevaton of the top of the tree are 21° 19' and 16°20'.
1) Convert the angles to decimal form:
19' * 1°/60' = 0.32° => 21° 19' = 21.32°
20' * 1°/60' = 0.33° => 16° 20' = 16.33°
2) Deduce the trigonometric ratios from the verbal information.
You can form a triangle with
- horizontal leg x + 65 feet
- elevation angle 16.33°
- vertical leg height of the tree, h
=> trigonometric ratio: tan (16.33) = h /( x + 65) => h = (x+65) * tan(16.33)
You can form a second triangle with:
- horizontal leg x
- elevation angle 21.32°
- vertical leg height of the tree, h
=> trigonometric ratio: tan(21.32) = h / x => h = x * tan(21.32)
Now equal the two expressions for h:
(x+65)*tan(16.33) = x*tan(21.32)
=> x*tan(16.33) + 65*tan(16.33) = x*tan(21.32)
=> x*tan(21.32) - x*tan(16.33) = 65*tan(16.33)
=> x = 65*tan(16.33) / [ tan(21.32) - tan(16.33) ] = 195.73 feet
=> h = 195.73 * tan(21.32) = 76.39 feet.
Answer: 76.39 feet
Answer:
Step-by-step explanation:
9h+5h(5h-5760)-2+12=y
<span>The cube’s sides measures 6 inches and the measurement for
the rectangular box is that it is 10 inches long, 4 inches thick and 4 inches
high. To compute for the volume of a cube you must use the formula of V = a3
and for the rectangular prism is V = l x w x h.</span>
<span>Cube: V = 6^3
</span> <span>V = 216 inches^3</span>
<span>Rectangular Prism: V
= 10 x 4 x 4</span>
<span>
V
= 160 inches^3</span>
To identify how much greater the volume the cube from the
rectangular box we subtract their volumes.
N = C – R where N stands for the unknown C for the volume of
cube and R for the volume of Rectangular Box
<span>
N = 216 inches^3 – 160 inches^3
</span>
<span>N = 56 inches^3</span>
<span>
So the cube is 56 inches3 greater than the
rectangular box.</span>
Answer:
its the top right
Step-by-step explanation:
x before y
B b b b b b b b b b b b b b b b b b b b b b b b b b b b b b.
