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3 years ago

Qual a resposta dessa expressão numérica? 3-10³-3.10².2².1²

1 answer:

6 0

I don't understand your language and I don't know which language is this but I try to answer your question. 3-1000-3*100*4*1 3-1000-1200 3-2200 =-2197

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How do i solve 2x-y=9

devlian [24]

20 with a number minus what will equal 9. ^_^

3 0

3 years ago

How to use a protractor.

damaskus [11]

Answer:

You can see below!

Step-by-step explanation:

Basically, a protractor is used to measure angles. You probably have a semi-circle shaped one. Looking at the bottom middle of the protractor should show you lines intersecting each other at a point. If you have an angle on a piece of paper, place that point on the ends of the line segments making up the angle. Then, check where each line of the angle crosses the numbers on the outer rim. That shows you the measure of the angle you are examining. It can be a bit tricky, but with practice you'll get it in no time!

8 0

2 years ago

Why is a parallelogram not the same type of quadrilateral as a trapezoid?

Liula [17]

A parallelogram has two pairs of opposite sides. A trapezoid only has one pair of parallel sides.

4 0

3 years ago

How many tiles of 10cm by a 6cm will be needed to pave a rectangular path of 5m by 3m

kherson [118]

Answer:

2500 tiles

Step-by-step explanation:

convert the path to the same units, one m = 100 cm

path= 500 cm x 300 cm

path area = 150,000 cm^2

each tile = 10x6 = 60 cm^2

150,000/60 = 2500 tiles

6 0

2 years ago

The attention span of children (ages 3 to 5) is claimed to be Normally distributed with a mean of 15 minutes and a standard devi

Agata [3.3K]

Answer:

If the observed sample mean is greater than 17.07 minutes, then we would reject the null hypothesis.

Step-by-step explanation:

We are given the following in the question:

Population mean, μ = 15 minutes

Sample size, n = 10

Alpha, α = 0.05

Population standard deviation, σ = 4 minutes

First, we design the null and the alternate hypothesis

$H_{0}: \mu = 15\text{ minutes}\\H_A: \mu > 15\text{ minutes}$

Since the population standard deviation is given, we use one-tailed z test to perform this hypothesis.

Formula:

$z_{stat} = \displaystyle\frac{\bar{x} - \mu}{\frac{\sigma}{\sqrt{n}} }$

Now, $z_{critical} \text{ at 0.05 level of significance for one tail} = 1.64$

Thus, we would reject the null hypothesis if the z-statistic is greater than this critical value.

Thus, we can write:

$z_{stat} = \displaystyle\frac{\bar{x} - 15}{\frac{4}{\sqrt{10}} } > 1.64\\\\\bar{x} - 15>1.64\times \frac{4}{\sqrt{10}}\\\bar{x} - 15>2.07\\\bar{x} > 15+2.07\\\bar{x} > 17.07$

Thus, the decision rule would be if the observed sample mean is greater than 17.07 minutes, then we would reject the null hypothesis.

6 0

3 years ago