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Leya [2.2K]
3 years ago
15

For what value of k will the points of simultaneous equations have no solution?

Mathematics
1 answer:
RSB [31]3 years ago
3 0

Answer:

k = -4.

Step-by-step explanation:

k = -4 because that would produce the system:

y = -4x - 7

y = -4x + 2

y cannot have 2 different values at the same time.

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An average of 145 people visited a 4-day exhibition on the first 3 days. Another 205 people visited the exhibition on the fourth
Alenkinab [10]

Answer:

160 visitors.

Step-by-step explanation:

Given:

An average of 145 people visited a 4-day exhibition on the first 3 days, <u>means here average people visited in 3 days is given 145.</u>

Average = 145

Number of people, n = 3

Another 205 people visited the exhibition on the fourth day.

To find:

What is the average number of visitors per day ?

Solution:

<u>First of all we will find total number of people visited in 3 days:-</u>

As we know:

Average=\frac{Sum\ of\ observation}{number\ of\ observation}

145=\frac{Sum\ of\ observation}{3}\\

Multiplying both sides by 3

145\times3=\frac{Sum\ of\ observation}{3}\times3\\435=Sum\ of\ observations

Thus, we found that total number of people visited in 3 days is 435 and as 205 people visited in fourth day, then total number of people increased to

435 + 205 = 640

Now, sum of total observations( total number of people ) = 640

And number of observation ( number of days ) = 4

Now, we will calculate average number of visitors visit per day :-

Average=\frac{Sum\ of\ observation}{number\ of\ observation}

             =\frac{640}{4} \\=160\ visitors

Thus, the average number of visitors per day is 160 visitors.

             

6 0
3 years ago
Work out 27 ÷ 9 + 9 <br> Work out 4 + 5 x 3<br> Work out -9 + -4<br> ) Work out 9 - -5
san4es73 [151]

Answer:

1. 27/9=3+9=12

2. 4+5x3=5x3=15+4=19

3. -9+-4=-13

4. 9--5=14

7 0
3 years ago
Read 2 more answers
BRAINLIESTT ASAP! PLEASE HELP ME :)
Yuki888 [10]

Let's say we placed dominoes close together such that they only fell over one way: to the right hand side. Let's call the dominoes A and B.

Domino A is to the left of domino B. If we push over domino A, then it will hit domino B to cause it to fall over as well. We have a mini chain reaction of sorts. The fall of A triggers the fall of B, but not the other way around.

For this problem, we can think of domino A as "Jillian gets a raise" and domino B as "she will buy a new car". The raise causes her to get a new car, but not vice versa.

Since we're told in the last sentence she definitely got the raise, this must mean she will definitely get the new car.

In terms of symbols, the law of detachment is stated as

  • If P, then Q
  • P is true
  • Therefore Q is true

Side note: some books might use the term "modus ponens" instead of "law of detachment". They're the same thing.

3 0
3 years ago
To celebrate 25 years in business, the furniture store is having a 25% off sale on all their furniture. Estimate the new price b
ICE Princess25 [194]

Answer:

Step-by-step explanation:

159.39(1-25/100)

159.39(100-25)/100

159.39(75)/100

159.39(0.75)

$119.54

5 0
3 years ago
For which value of theta is cot theta equal to cos theta?
Oksi-84 [34.3K]

Answer:

\frac{cos \theta}{sin \theta}= cos \theta

If we multiply by cross we got:

cos \theta = sin \theta cos \theta

We can divide both sides of the last equation by cos \theta and we got:

sin \theta = 1

And if we apply arcsin in both sides we got:

\theta = arcsin (1) = \frac{\pi}{2}

And the best solution would be:

C) pi/2

Step-by-step explanation:

For this case we want to solve the following equation:

cot \theta = cos \theta

And we know that by definition cot \theta = \frac{cos \theta}{\sin \theta}

And replacing we got:

\frac{cos \theta}{sin \theta}= cos \theta

If we multiply by cross we got:

cos \theta = sin \theta cos \theta

We can divide both sides of the last equation by cos \theta and we got:

sin \theta = 1

And if we apply arcsin in both sides we got:

\theta = arcsin (1) = \frac{\pi}{2}

And the best solution would be:

C) pi/2

8 0
3 years ago
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