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-BARSIC- [3]
4 years ago
10

My favorite songdress

Mathematics
1 answer:
Oxana [17]4 years ago
7 0

Answer:

Any dress with ur favorite color

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3/2 [4 2 9 -6 8 -7 10 -4 18]
vladimir2022 [97]

Answer:

Step-by-step explanation:

3/2*(-767)

Multiplying a postive and a negative = a negative

= -3/2*767

=-2301/2

3 0
3 years ago
Rosa recorded the height (in centimeters) of a pea plant over a 10-day period for a science experiment. Please help me with this
katrin [286]

Answer:

option a)

y = m(0.5) + 1.8

Step-by-step explanation:

Equation

<h3>y = mx + c</h3>

represent the equation of straight line

here m = gradient of straight line

         c = y-intercept

First find the gradient of the graph

<h3>m = y2 - y1 / x2 - x1</h3>

    = 4 - 3 / 4 - 2

    = 1 / 2

Put the values in the equation of straight line

y =mx + c

4 = 1/2(4) + c

c = 2

y = 1/2x + 2

which is approximately equal to y = 0.5x + 1.8

7 0
3 years ago
Describe the relationship between n and 4 that will make the value of the expression 7×n/4 great her than 7
nadezda [96]
If you want an answer greater that 7, your fraction needs to be greater than 1.
n can be any number greater than 4

7 \times  \frac{4}{4}  = 7
7 \times  \frac{8}{4}  = 14
5 0
4 years ago
Circle O, with center (x, y), passes through the points A(0, 0), B(–3, 0), and C(1, 2). Find the coordinates of the center of th
balandron [24]
The answer:

the main formula of the circle's equation is 
(x-a)²+ (y-b)² = R²
where C(a, b) is the center of the circle
R is the radius

if a point A(x', y') passes through the circle, so the equation of the circle can be written as 
(x'-a)²+ (y'-b)² = R², and that is  a main formula.


<span>Circle O, with center (x, y), passes through the points A(0, 0), B(–3, 0), and C(1, 2), so we have exactly three equation:
</span>
(0-x)² + (0-y)² = R², circle O passes through A
x²+y²= R²
(-3 -x)² + (0-y)² = R², circle O passes through B
(-3 -x)² + (y)² = R²
(1-x)² + (2-y)² = R², circle O passes through A
(1-x)² + (2-y)² = R²

and we know that R= OA = OC= OB, 
OA=R= sqrt( (0-x)² + (0-y)² ) = OB = sqrt((-3 -x)² + (0-y)²), this implies

x²+y² = (-3 -x)² + (0-y)² , it implies x² = 9+ x² + 6x , and then -9/6=x, x= -3/2
and when OA = OC
x²+y² =(1-x)² + (2-y)²  so, x²+y² =1+x²-2x +4+y²-4y, therefore -5= -2x -4y
 -5= -2x -4y, when x = -3 /2   we obtain y = 2

the center is C(-3/2, 2)
7 0
4 years ago
What is the equation in point-slope form for the line parallel to y=-8x - 5 that contains j(-2, 9)
Julli [10]

Answer:

y - 9 = -8(x + 2)

Step-by-step explanation:

What is the equation in point-slope form for the line parallel to y=-8x - 5 that contains j(-2, 9)

Step 1

y intercept =

y = mx + b

y=-8x - 5

m = -8, b = -5

Point slope form

y - y1 =m( x - x1)

We are given coordinates:

j(-2, 9) = (x1, y1) where ,

x1 = -2

y1 = 9

Hence, our point slope form equation is:

y - 9 = -8(x -(-2))

y - 9 = -8(x + 2)

5 0
3 years ago
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