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lapo4ka [179]
3 years ago
7

Shapes I and II are

Mathematics
1 answer:
xz_007 [3.2K]3 years ago
8 0
What is the meaning of this question
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Which is the best estimate of 11
vekshin1

Answer:

4 would be the answer hopefully

5 0
2 years ago
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I'm not sure if I am right and just want to make sure I got the right answer
djyliett [7]

Answer:

The answer is 9

Step-by-step explanation:

The answer is 9

7 0
2 years ago
Jason and Maria are playing a board game in which three dice are tossed to determine a player's move. Find each probability for:
fredd [130]
Tossing a die will have 6 possible outcomes. Those are having sides that are number 1 to 6. The sample space of tossing 3 dice is equal to 6³ which is equal to 216. Now for the calculation of probabilities,

P(two 5s) = (1 x 1 x 5)/216
As we have to have the 5 in the die for two times, then for the 1 time, we can have all other numbers except 5. The answer is 5/216. 

P(three 5s) = (1 x 1 x 1)/216   = 1/216

P(one 5 or two 5s)  = (1 x 5 x 5)/216 + (1 x 1 x 5)/216 = 5/36
6 0
2 years ago
3 + 1 < 10 solve, then graph the solution
ryzh [129]

           3 + 1 < 10

There's no question there, and nothing to solve.  That's a simple statement
which, after simplifying it slightly, says " 4 < 10 ".

A statement with which, I'm sure, we can all agree.


3 0
3 years ago
At an university 70% of the students who attend stay on campus. If 1,380 of the students who attend live off campus, what is the
Alborosie

Answer:

4600

Step-by-step explanation:

We can write a proportion to find the total amount who attend university using the information given. A proportion is two equivalent ratios set equal to each other. Since 70% live on campus, then 30% live off campus and we are told that number is 1,380.

\frac{30}{100}=\frac{1380}{y}

We will cross multiply the numerator of one ratio with denominator of the other. And then solve for y.

30y=100(1380)

30y=138000

y=4600.

There are 4600 students who attend the university.

7 0
2 years ago
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