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lapo4ka [179]
3 years ago
7

Shapes I and II are

Mathematics
1 answer:
xz_007 [3.2K]3 years ago
8 0
What is the meaning of this question
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A school conducts 27 tests in 36 weeks. Assume the school conducts tests at a constant rate. What is the slope of the line that
Alex17521 [72]

Answer:

3/4

Step-by-step explanation:

slope=rate of taking tests=27/36=3/4

7 0
4 years ago
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Solve using elimination
Margarita [4]
Well, it was good that you did subtract A from B to get
0=x^2-152x
then factor out the x (what do you mean it cannot be factored?)
0=x(x-152)
x=0 or 0=x-152 so x=152

so on day 0 and day 152

3 0
3 years ago
Tomas ran a Lucky Dip stall.
oksian1 [2.3K]

Answer:

637

Step-by-step explanation:

Ticket ending 00= £12 * 7 = £84  

Tickets ending 5 = £1.5 * 75 = £112.5  

£84+£112.5=£196.5  

Price money + Profit: £196.5+£163= 356

356/£0.5 = 719 total tickets sold

719- 82 (WINNING TICKETS) = 637 losing tickets sold

3 0
3 years ago
Solve Q²= a(p²-b²)/p in form of y=mx+c
umka2103 [35]

Answer:

We want to rewrite:

q^2 = a*(p^2 - b^2)/p

as a linear equation, in the form:

y = m*x + c

So we start with:

q^2 = a*(p^2 - b^2)/p

we can expand the left side to get:

q^2 = (a/p)*p^2 - (a/p)*b^2

q^2 = a*p - (a/p)*b^2

Now we can ust define:

a*p = c

Then we can replace that to get:

q^2 = -(a/p)*b^2 + c

now we can replace:

q^2 = y

b^2 = x

Replacing these, we get:

y = -(a/p)*x + c

finally, we can replace:

-(a/p) = m

then we got the equation:

y = m*x + c

where:

y = q^2

x = b^2

c = a*p

m = -(a/p)

4 0
3 years ago
One dozen cookies cost $5.50. At that rate, how much does one cookie cost?
myrzilka [38]

Answer:

0,458$

Step-by-step explanation:

8 0
3 years ago
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