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3 years ago

Which point is located in quadrant IV (-2,-4) (-2,4) (2,-4) (2'4)

Mathematics

2 answers:

m_a_m_a [10]3 years ago

6 0

Answer:

(2,-4)

Step-by-step explanation:

Quadrant IV is in the bottom right corner. Any y-value below the x-axis is negative while any x-value on the right side of the y-axis is positive.

LenKa [72]3 years ago

3 0

(2,-4) is the answer because its the opposite of quadrant ii

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If the perimeter of the triangle is 73 mm, find the value of x.

Dmitry_Shevchenko [17]

Answer:

27 mm

Step-by-step explanation:

The perimeter of the triangle is the sum of all sides lengths. In given triangle

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4 years ago

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Negitive 78 squared plus 3 a minus 9 minus 5 8th squared minus 6 a minus 4

Lorico [155]

Answer:

-6125

Step-by-step explanation:

negative 78 squared = -6084

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I got confused by "8th" and "a minus" do you mean 3a, and 6a?

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3 years ago

If AB=7x, CB=5x+8 and BD AC what is the length of CB

seropon [69]

Answer:

x = 4

CB = 28

Step-by-step explanation:

In triangle ABC,

AB = CB..... (given)

Therefore,

7x = 5x + 8

7x - 5x = 8

2x = 8

x = 8/2

x = 4

CB = 5x + 8 = 5*4 + 8 = 20 + 8 = 28

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3 years ago

What is the completely factored form of 6 x squared minus 13 x minus 5?

777dan777 [17]

Answer:

$(2x-5)(3x+1)$

Step-by-step explanation:

The given quadratic trinomial is $6x^2-13x-5$

Where a=6, b=-13 and c=-5

$ac=-30$

The factors of -30 that add up to -13 are -15,2

We split the middle term to get:

$6x^2+2x-15x-5$

Factor by grouping:

$2x(3x+1)-5(3x+1)$

These completely factors to:

$(2x-5)(3x+1)$

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3 years ago

the sum of two numbers is 13 and their difference is 3. Write and solve a system of equations to find the value of the two numbe

AnnyKZ [126]

The first thing you want to do is factor out 13. It can ether be (1, 12), (2, 11), (3, 10), (4, 9), (5, 8), or (6, 7). In this case, it says the difference of the two numbers is 3, so you subtract the two numbers 8 and 5 to get three. Your answer is 8 and 5

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3 years ago

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