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Readme [11.4K]
3 years ago
11

A home store donated a percent of everybody sale to charity. The total sales were $6,550 so the store donated $393. What percent

of $6,550 was donated to charity?
Mathematics
1 answer:
Andrej [43]3 years ago
5 0

Answer:

6%

Step-by-step explanation:

393/6550=0.06

0.06=6%

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48% of what number is 108? A. 44.4 B. 51.84 C. 225 D. 5184
Ivan
Let the number = x.

48% of x = 108

(48/100)x = 108

x  =  108 * 100 /48  = 225          use your calculator.

Answer is option C.

8 0
3 years ago
Read 2 more answers
10 is 25% of what number?
Zanzabum

Answer:

40

Step-by-step explanation:

25%= \frac{1}{4}

10×4=40

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3 years ago
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Simplify....... <br><br><br><br>-9-6c-j​
marin [14]

Answer: −6c−j−9

Step-by-step explanation:

3 0
3 years ago
Domain and range of the inequality y&lt;√x+3 +1
Margaret [11]

The domain of the given inequality is y>1.

<h3>What is Inequality?</h3>

An inequality is a relation which makes a non-equal comparison between two numbers or other mathematical expressions.

Here, given inequality:

              y < \sqrt{x+3}+1

Related equation:

             y = \sqrt{x+3}+1

The equation defined as,

    x+3 > 0

    x > -3

In the given inequality, the sign of inequality is <, it means the points on the boundary line are not included in the solution set. Thus, -3 is not included in the domain.

So, the domain of the given inequality is x>-3.

We know that,

    \sqrt{x+3} \geq 0

adding 1 on both sides, we get

  \sqrt{x+3} + 1 \geq  1

      y ≥ 1

The points on the boundary line are not included in the solution set. Thus, 1 is not included in the range.

Thus, the domain of the given inequality is y>1.

Learn more about Inequality from:

brainly.com/question/20383699

#SPJ1

6 0
2 years ago
44. Express each of these system specifications using predicates, quantifiers, and logical connectives. a) Every user has access
DENIUS [597]

Answer:

a. ∀x (User(x) → (∃y (Mailbox(y) ∧ Access(x, y))))

b. FileSystemLocked → ∀x Access(x, SystemMailbox)

c. ∀x ∀y ((Firewall(x) ∧ Diagnostic(x)) → (ProxyServer(y) → Diagnostic(y))

d. ∀x (ThroughputNormal ∧(ProxyServer(x)∧ ¬Diagnostic(x))) → (∃y Router(y)∧Functioning(y))

Step-by-step explanation:

a)  

Let the domain be users and mailboxes. Let User(x) be “x is a user”, let Mailbox(y) be “y is a mailbox”, and let Access(x, y) be “x has access to y”.  

∀x (User(x) → (∃y (Mailbox(y) ∧ Access(x, y))))  

(b)

Let the domain be people in the group. Let Access(x, y) be “x has access to y”. Let FileSystemLocked be the proposition “the file system is locked.” Let System Mailbox be the constant that is the system mailbox.  

FileSystemLocked → ∀x Access(x, SystemMailbox)  

(c)  

Let the domain be all applications. Let Firewall(x) be “x is the firewall”, and let ProxyServer(x) be “x is the proxy server.” Let Diagnostic(x) be “x is in a diagnostic state”.  

∀x ∀y ((Firewall(x) ∧ Diagnostic(x)) → (ProxyServer(y) → Diagnostic(y))  

(d)

Let the domain be all applications and routers. Let Router(x) be “x is a router”, and let ProxyServer(x) be “x is the proxy server.” Let Diagnostic(x) be “x is in a diagnostic state”. Let ThroughputNormal be “the throughput is between 100kbps and 500 kbps”. Let Functioning(y) be “y is functioning normally”.  

∀x (ThroughputNormal ∧(ProxyServer(x)∧ ¬Diagnostic(x))) → (∃y Router(y)∧Functioning(y))

4 0
3 years ago
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