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julsineya [31]
3 years ago
11

PointQ′(prime)is the image of Q(-4,7)Q(−4,7)Q, left parenthesis, minus, 4, comma, 7, right parenthesis under a translation by 44

4 units to the right and 222 units down.
What are the coordinates of Q'(prime)?
Mathematics
1 answer:
Mars2501 [29]3 years ago
3 0

Answer:

5,2

(-7+12=5,-6=8=2) Hope this helps you!!

Step-by-step explanation:

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lana [24]

Answer:

ridiculous

Step-by-step explanation:

tssssk *extra characters*

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3 years ago
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1. (5 points) At 6pm, ghost A is 5 kilometers due west of ghost B. Ghost A is flying west
zaharov [31]

Answer:

The distance between the ghost changes at 10 pm approximately at a rate of 24.981 kilometers per hour.

Step-by-step explanation:

At first we assume that north and east directions both represent positive quantities. Let suppose that \vec r_{A,o} = (0\,km,0\,km) and \vec r_{B,o} = (5\,km, 0\,km). If both ghosts moves at constant velocity such that \vec v_{A} = \left(-15\,\frac{km}{h}, 0\,\frac{km}{h} \right) and \vec v_{B} = \left(0\,\frac{km}{h},20\,\frac{km}{h}  \right), then the final positions of both ghosts are, respectively:

Ghost A

\vec r_{A} = \vec r_{A,o}+t\cdot \vec v_{A} (Eq. 1)

Ghost B

\vec r_{B} = \vec r_{B,o}+t\cdot \vec v_{B} (Eq. 2)

Where t is the time, measured in hours.

Then, the equations of motion of each ghost are, respectively:

Ghost A

\vec r_{A} = (0\,km,0\,km)+t\cdot \left(-15\,\frac{km}{h}, 0\,\frac{km}{h}  \right)

\vec r_{A} = \left(-15\cdot t, 0)\,\,\,\left[km \right]

Ghost B

\vec r_{B} = (5\,km, 0\,km)+t\cdot \left(0\,\frac{km}{h}, 20\,\frac{km}{h}  \right)

\vec r_{B} = (5, 20\cdot t)\,\,\,\left[km\right]

Then, the distance between both ghosts is:

\vec r_{B/A} = (5,20\cdot t)-(-15\cdot t, 0)\,\,\,[km]

\vec r_{B/A} =(5+15\cdot t, 20\cdot t)\,\,\,[km] (Eq. 3)

The magnitude of the relative is represented by the following Pythagorean identity:

r^{2}_{B/A} = (5+15\cdot t)^{2}+(20\cdot t)^{2}

Then, we find the rate of change of the relative distance (\dot r_{B/A}), measured in kilometers per hour, by implicit differentiation:

2\cdot r_{B/A}\cdot \dot r_{B/A} = 2\cdot (5+15\cdot t)\cdot 15+2\cdot (20\cdot t)\cdot 20

r_{B/A}\cdot \dot r_{B/A} = 15\cdot (5+15\cdot t)+20\cdot (20\cdot t)

\dot r_{B/A} = \frac{75+625\cdot t}{r_{B/A}}

\dot r_{B/A} = \frac{75+625\cdot t}{\sqrt{(5+15\cdot t)^{2}+(20\cdot t)^{2}}} (Eq. 4)

If we know that t = 4\,h, then the rate of change of the relative distance at 10 PM is:

\dot r_{B/A} = \frac{75+625\cdot (4)}{\sqrt{[5+15\cdot (4)]^{2}+[20\cdot (4)]^{2}}}

\dot r_{B/A} \approx 24.981\,\frac{km}{h}

The distance between the ghost changes at 10 pm approximately at a rate of 24.981 kilometers per hour.

4 0
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Each school year, seventh graders who study Life Science participate in a in a special field trip to the city zoo. In 2010, the
ad-work [718]
A Yes
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C 15:1
D 120×15= $1800.00
E $1425÷15= 95 students
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702 miles is how many hours flight
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Answer:

It depends on the speed and acceleration of the plane.

But it's approximately 2 hr

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The answer will be 53.00 dollars
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