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Svetach [21]
4 years ago
9

3/12 and 5/x are equivalent ratios. Solve for x

Mathematics
2 answers:
GaryK [48]4 years ago
6 0
3/12=5/x
1/4=5/x
times both sides by 4x aka cross multiply
1x=20
x=20
AleksandrR [38]4 years ago
3 0
I hope this helps you


3/12=5/x


1/4=5/x


x=4.5


x=20
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Find the 23rd term of the arithmetic sequence 17, 19, 21, 23, ...
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3 years ago
Given three balls and four boxes. Assume the boxes are numbered 1, 2 ,3 and 4.Place the ball one by one into the boxes randomly.
KengaRu [80]

Answer:

The value of E(X) is 1.56

Step-by-step explanation:

Number of Boxes=4

Number of Balls =3

If X is the number of box in which the balls are than the number of balls in the box are given as ((4-X)+1)^3

Number of ways such that all the balls are in the box number 4, no balls in the first three boxes is given as n(x=4)=1^3=1

Number of ways such that all the balls are in the box number 3,  is given as n(x=3)=n(x=2)-n(x=4)=2^3-1^3=7

Number of ways such that all the balls are in the box number 2,  is given as n(x=2)=n(x=1)-n(x=3)=3^3-2^3=19

Number of ways such that all the balls are in the box number 1,  is given as n(x=1)=n(x=4)-n(x=3)=4^3-3^3=37

So the total number of ways are

n(total)=n(x=4)+n(x=3)+n(x=2)+n(x=1)

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So Probabilities are given as

p(x=1)=n(x=1)/n(total)=37/64

p(x=2)=n(x=2)/n(total)=19/64

p(x=3)=n(x=3)/n(total)=7/64

p(x=4)=n(x=4)/n(total)=1/64

So the E(x) is given as

E(X)=\sum^{n}_{i=1}p_ix_i\\E(X)=\sum^{4}_{i=1}p_ix_i\\E(X)=x_1p_1+x_2p_2+x_3p_3+x_4p_4\\E(X)=1\times\dfrac{37}{64}+2\times\dfrac{19}{64}+3\times\dfrac{7}{64}+4\times\dfrac{1}{64}\\E(X)=\dfrac{25}{16}=1.56

So the value of E(X) is 1.56

5 0
4 years ago
Find the points of intersection of the equation: xy=2 and x+y =4
Blizzard [7]

Answer:\Large\boxed{(2+\sqrt{2},~2-\sqrt{x} )~~and~~ (2-\sqrt{2},~2+\sqrt{x} )}

Step-by-step explanation:

<u>Given the system of equations</u>

1)~xy=2

2)~x+y=4

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xy=2

xy\div x=2\div x

y=\dfrac{2}{x}

<u>Current system</u>

1)~y=\dfrac{2}{x}

2)~x+y=4

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x+(\dfrac{2}{x} )=4

<u>Multiply x on both sides</u>

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<u>Use the quadratic formula to solve for the x value</u>

x=\dfrac{-(-4)\pm\sqrt{(-4)^2-4(1)(2)} }{2(1)}

x=2\pm\sqrt{2}

<u>Substitute the x value into one of the equations to find the y value</u>

xy=2

(2+\sqrt{2} )y=2

y=2-\sqrt{2}

OR

xy=2

(2-\sqrt{2} )y=2

y=2+\sqrt{2}

Therefore, the points of intersection are

\Large\boxed{(2+\sqrt{2},~2-\sqrt{x} )~~and~~ (2-\sqrt{2},~2+\sqrt{x} )}

Hope this helps!! :)

Please let me know if you have any questions

5 0
1 year ago
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