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2 answers:
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Answer:
Explanation:
Alright so the way to do this is to use properties of integrals to make our life easier.
So we have:
So lets break this up into two different integrals that represent the same area.
Lets think about what is going on up there. The integral from four to zero gives us the area under the curve of f(x) from four to zero. If we subtract this from the integral from one to zero (the area under f from one to zero) we are left with the area under f from four to one! Hence:
But since we have these values we can say that:
-3 - 2 = -5
Which means that = -5
So now we can evaluate
Lets first break up our integrand into two integrals
=
Now we can evaluate this:
We know that = -5
So:
where x is evaluated at 4 to 1 so
-15 + 2(3)
So we are left with -15 + 6 = -9
Answer is a
*The correct answer is IJ = JK
•explanation:
Given:
AB is the perpendicular bisector of
IK. ⇒ AB divides the line segment IK in two equal parts i.e. IJ = JK and the angle formed at the point of intersection J is 90° ⇒ ∠AJI = 90°. In ΔAIJ, By angle sum property of a triangle ∠AJI + ∠AIJ + ∠IAJ = 180° ( But ∠AJI = 90° ) ∠AIJ + ∠IAJ = 90° ⇒ ∠IAJ < 90° So, ∠IAJ is not a right angle. Its not given IK is a perpendicular bisector so AJ = BJ need NOT be true. As A does not lie on the line IK so A can not be the mid point of IK.
•Hence, we conclude the correct statement is IJ = JK
*The correct answer is IJ = JK
•explanation:
Given:
AB is the perpendicular bisector of
IK. ⇒ AB divides the line segment IK in two equal parts i.e. IJ = JK and the angle formed at the point of intersection J is 90° ⇒ ∠AJI = 90°. In ΔAIJ, By angle sum property of a triangle ∠AJI + ∠AIJ + ∠IAJ = 180° ( But ∠AJI = 90° ) ∠AIJ + ∠IAJ = 90° ⇒ ∠IAJ < 90° So, ∠IAJ is not a right angle. Its not given IK is a perpendicular bisector so AJ = BJ need NOT be true. As A does not lie on the line IK so A can not be the mid point of IK.
•Hence, we conclude the correct statement is IJ = JK