Answer:
Please find the expected genotypes and phenotypes of the progenies of each cross below.
Explanation:
In the MN blood-group locus of the gene, alleles LM and LN exhibit codominance i.e one allele is not dominant or recessive to the other, hence, they are both expressed when they occur in a heterozygous state (MN).
Considering the following crosses (find the punnet square attached);
a)LMLM x LMLN - The progeny are LMLM and LMLN in the genotypic ratio 1:1. Phenotypic ratio is Blood type M (1) : blood type MN (1)
b) LNLN x LNLN - The progeny are all LNLN offsprings with a phenotypic and genotypic ratio 4:0. All offsprings will have a blood type N (4)
c) LMLN x LMLN - The progenies are LMLM, LMLN and LNLN in the genotypic ratio 1:2:1 respectively. The phenotypic ratio is Blood type M (1) : L
Blood type MN (2) : Blood type N (1)
d) LMLN x LNLN - The progeny are LMLN and LNLN with genotypic ratio 1:1 and phenotypic ratio blood type MN (1) : blood type N (1)
e) LMLM x LNLN - The progeny are all LMLN offsprings with penotypic ratio blood type MN (4)
10kg mass and a 10kg mass at 10km apart
Answer:
d. Character displacement
Explanation:
Character displacement is the phenomenon in which the similar species living in the same geographical region with similar niches differentiate in order to reduce their niche overlap and avoid competitive exculsion. Just like in this case of two- spot and three -spot avenger beetles as their timmings for hunting is different where their ranges overlap. So it's the good example of character displacement,
To solve for the mass of a substance is to simply get the
product of volume and density, that is:
mass = density * volume
So calculating for mass:
mass = (2.76 g / cm^3) * 6 cm^3
mass = 16.56 g
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