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Scilla [17]
3 years ago
9

What is the solution set for x2+25=0

Mathematics
1 answer:
Masja [62]3 years ago
7 0

Step-by-step explanation:

{x}^{2}  + 25 = 0 \\  \therefore {x}^{2}  =  - 25 \\ \therefore {x}  =  \sqrt{ - 25}  \\  \therefore {x}  =   \pm\sqrt{ - 1 \times 25}  \\ \therefore {x}  = \pm  \sqrt{  25}  \times  \sqrt{ - 1}  \\ \therefore {x}  =  \pm5 \: i  \\ \therefore {x}  = \{ - 5i, \:  \: 5i \} \: \\  is \: the \: solution \: set.

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icang [17]

Answer:

coefficient of x: 2

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Step-by-step explanation:

To solve this problem, first we need to sum the polynomials A and B, then we need to check the coefficients of x, y and z.

The sum of the polynomials is:

A + B = 5z + 4x^2 - 6y + 2 + 2x + 9y - 12z - 2

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Answer:

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