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3 years ago

What is the solution set for x2+25=0

Mathematics

1 answer:

Masja [62]3 years ago

7 0

Step-by-step explanation:

${x}^{2} + 25 = 0 \\ \therefore {x}^{2} = - 25 \\ \therefore {x} = \sqrt{ - 25} \\ \therefore {x} = \pm\sqrt{ - 1 \times 25} \\ \therefore {x} = \pm \sqrt{ 25} \times \sqrt{ - 1} \\ \therefore {x} = \pm5 \: i \\ \therefore {x} = \{ - 5i, \: \: 5i \} \: \\ is \: the \: solution \: set.$

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Vlad1618 [11]

Answer:

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Step-by-step explanation:

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3 years ago

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Answer:

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2 years ago

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ICE Princess25 [194]

Using derivatives, it is found that the x-values in which the slope belong to the interval (-1,1) are in the following interval:

(-15,-10).

<h3>What is the slope of the tangent line to a function f(x) at point x = x0?</h3>

It is given by the derivative at x = x0, that is:

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In this problem, the function is:

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Hence the derivative is:

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For a slope of 1, we have that:

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Hence the interval is:

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More can be learned about derivatives and tangent lines at brainly.com/question/8174665

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Step-by-step explanation:

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