If a video game that costs $75 is on sale for 15% off, what is the new price of the video game?
2 answers:
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<h3>Rate of the boat in still water is 70 km/hr and rate of the current is 15 km/hr</h3><h3><u>Solution:</u></h3>
Given that,
A motorboat travels 165 kilometers in 3 hours going upstream and 510 kilometers in 6 hours going downstream
Therefore,
Upstream distance = 165 km
Upstream time = 3 hours
<h3><u>Find upstream speed:</u></h3>Thus upstream speed is 55 km per hour
Downstream distance = 510 km
Downstream time = 6 hours
<h3><u>Find downstream speed:</u></h3>Thus downstream speed is 85 km per hour
<em><u>If the speed of a boat in still water is u km/hr and the speed of the stream is v km/hr, then</u></em>
Speed downstream = u + v km/hr
Speed upstream = u - v km/hr
Therefore,
u + v = 85 ----- eqn 1
u - v = 55 ----- eqn 2
Solve both
Add them
u + v + u - v = 85 + 55
2u = 140
u = 70
<em><u>Substitute u = 70 in eqn 1</u></em>
70 + v = 85
v = 85 - 70
v = 15
Thus rate of the boat in still water is 70 km/hr and rate of the current is 15 km/hr
Answer:
The weight of watermelon at the end of the trip is <u>500 kg.</u>
Step-by-step explanation:
Given:
The weight of watermelons is 1000kg.
At the beginning of the trip watermelon is 99% of the weight:
99% of 1000kg
kg
Now, at the end of the trip it is 98% of weight. So, let kg of water has been evaporated. So, remaining weight of the watermelon is
.
If kg of water is removed, then the amount of water left is
.
As per question, water now weighs 98% of the total weight. So,
98% of () =
(Bringing like terms on one side)
Therefore, the weight of watermelon at the end of the trip is given as:
Weight = = 1000 - 500 = 500 kg
Therefore, the watermelon weighs 500 kg at the end of trip.