Answer: p < 24
Step-by-step explanation: I'm assuming you mean solving for P
1. We want to get p alone and the first step would be to subtract 4 from both side which will give us: ⅔p < 16
2. Next step would to be multiplying by 3 from both sides and doing this will cancel out the 3 in the denominator giving you: 2p < 48
3. Now we have to divide both sides by 2 and we are done which gives us:
<u>p < 24</u>
<u></u>
Don't forget if we were to be dividing by a negative the sign would flip
(for example: -2p < 6 = p > 3) this isn't used in this problem but just a reminder if you see this in future problems
Answer:
-1
Step-by-step explanation:
4u-5v=23
-2(2u+4v=16) We multiply by -2 here to destroy u's.
4u-5v=23
-4u-8v=16 we addition both processes
-13v=39 so, v=-3
4u-5(-3)=23, 4u=8 so, u=2
u+v= -3+2= -1
Answer:
6/20 = 3/10
Step-by-step explanation:
Her brother gets the first treat. There are 2 grape treats out of 3+2 = 5 total; this is a probability of 2/5.
Maggie gets the second treat. There will still be 3 cherry treats left, but only 5-1 = 4 treats remaining; this is a probability of 3/4.
Together this gives us 2/5(3/4) = (2*3)/(5*4) = 6/20 = 3/10
Answer:
(1) a. 0.0009
(2) d. 0.640
(3)
- a. P(A and B) = 0.06.
- b. P(A or B) = 0.70.
(4)Not disjoint
(5) a. nearly 0.
(6)b. 0.919
Step-by-Step Explanation:
(1)Probability of a baby being born with a birth defect =3%=0.03
The probability that both babies have birth defects=0.03 X 0.03= 0.0009.
(2)The probability of contracting the influenza virus each year = 20%=0.2
Therefore, the probability of not contracting the influenza virus =1-0.2=0.8
The probability that neither baby catches the flu in a given year:
=0.8 X 0.8
=0.64
(3)
P(A)=0.1
P(B)=0.6
P(A or B)=P(A)+P(B)=0.1 + 0.6 =0.7
P(A and B)=P(A)XP(B)=0.1 X 0.6 =0.06
(4)
P(A)=0.2
P(B)=0.9
Event A and B cannot be disjoint.
(5)
The probability of an American woman aged 20 to 24 having Chlamydia infection 
The probability that three randomly selected women in this age group have the infection

(6)The probability of an American woman aged 20 to 24 not having Chlamydia infection 
The probability that three randomly selected women in this age group do not have the infection
