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STatiana [176]
3 years ago
9

Pleaseeee help meeeHow to solve this questions?(i) ?(ii) ?

Mathematics
1 answer:
aalyn [17]3 years ago
8 0
(i) The scale factor is 6 because of the ratio between the 2 given corresponding sides.
I don't know the second part, but I hope this helps regardless.

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8. Identify which equation is a graph of a vertical line.
Y_Kistochka [10]

Answer:

10x = 10.

Step-by-step explanation:

The equation will contain the  x variable only.

4 0
3 years ago
Please help me get the answer i’ll give you a thanks and 10 points pls
vitfil [10]
586 cm squared i believe
7 0
2 years ago
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Marissa bought 12.8 pounds of potatoes at $1.35 per pound how much did Marissa spend for the potatoes? Explain.
Yuri [45]
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5 0
1 year ago
A petrol kiosk p is 12 km due north of another petrol kiosk q. The bearing of a police station r from p is 135 degree and that f
tiny-mole [99]

Answer:

Distance between P and R is 40.15 km.

Step-by-step explanation:

From the picture attached,

Petrol kiosk P is 12 km due North of another petrol kiosk Q.

Bearing of a police station R is 135° from P and 120° from Q.

m∠QPR = 180° - 135° = 45°

m∠PQR = 120°

m∠PRQ = 180° - (m∠QPR +m∠PQR)

             = 180° - (45° + 120°)

             = 180° - 165°

             = 15°

Now we apply sine rule in ΔPQR to measure the distance between P and R.

\frac{\text{sin}(\angle QPR)}{\text{QR}}= \frac{\text{sin}(\angle PQR)}{\text{PR}}=\frac{\text{sin}\angle PRQ}{\text{PQ}}

\frac{\text{sin}(45)}{\text{QR}}= \frac{\text{sin}(120)}{\text{PR}}=\frac{\text{sin}(15)}{\text{12}}

\frac{\text{sin}(120)}{\text{PR}}=\frac{\text{sin}(15)}{\text{12}}

PR = \frac{12\text{sin}(120)}{\text{sin}(15)}

PR = 40.15 km

Therefore, distance between P and R is 40.15 km.

8 0
3 years ago
Which of the following is the best definition of a circle?
Leona [35]

Answer:

The set of all points on a plane equidistant to a given point

Step-by-step explanation:

"following"?

8 0
3 years ago
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