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3 years ago

Plz help with 13 use the Pythagorean theorem

Mathematics

1 answer:

tia_tia [17]3 years ago

3 0

Pythagorean Theorem:
a^2 + b^2 = c^2

26^2 + 18^2 = c^2
676 + 324 = c^2
1,000 = c^2
ratio
31.6 = c

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Please help me i really need help please help me please

jeka57 [31]

Answer:

pluto

Step-by-step explanation:

7 0

3 years ago

A 99% confidence interval for the population mean yields the following results: [−3.79, 5.86]. At the 1% significance level, wha

loris [4]

Answer:

Decision rule: Do not reject $H_o$ ; we cannot conclude that the mean differs from zero

Step-by-step explanation:

From the given information:

The null hypothesis and alternative hypothesis is given as:

$H_o: \mu = 0 \\ \\ H_1 : \mu \ne 0$

And the 99% confidence interval for the population mean $\mu$ is: [−3.79, 5.86]

The significance level ∝ = 1 - 0.99 = 0.01

We will notice that the 99% confidence interval for the population mean $\mu$ contains the null hypothesis mean value which is equal to zero.

Thus, we do not reject the null hypothesis at the significance level ∝ = 0.01

∴

Decision rule: Do not reject $H_o$ ; we cannot conclude that the mean differs from zero

3 0

3 years ago

Sarah is going to a higher a DJ for her party. DJ iceman charges an initial fee of $100 in addition to $21 per hour. DJ chomp ch

nalin [4]

First you make an equation and establish a variable.
x=amount of hours the DJs will charge the same amount
100+21x=150+15x
Now you solve for x and that will get you your answer.
100+21x=150+15x
-21x -21x
100=150-6x
-150 -150
-50=-6x
8.3333...=x
You can round the answer to $8.33
Hope I helped.

6 0

4 years ago

Please help on this one!! I need it in ASAP :(

lisov135 [29]

Answer:

Hey there! here's your answer

Step-by-step explanation:

Speed = distance/Time

Speed = 3/5 ÷ 1/2

Speed = 3/5 * 2

Speed = 6/5 mph or 1.2 mph.

5 0

3 years ago

Read 2 more answers

Divide 6k2-15-5 by 3k

TEA [102]

Based on the question above, I believe that '6k2' would be $(6k^2)$ . So by this, I would continue to with the following expression as: $6k^2-15-5\div3k$

$Simplify: \frac{5}{3} \\ \\ ((6 * (k2)) - 15) - ( \frac{5}{3} *k) \\ \\ ((2*3k^2) - 15) - \frac{5k}{3} \\ \\ \boxed{\boxed{6k^2 - 15 = \frac{6k^2-15}{1} = \frac{(6k^2-15)*3}{3} }} \\ \\ (pull \ out \ like \ terms) \\ \\ 6k^2 - 15 = 3 * (2k^2 - 5) \\ \\ Factoring: 2k^2 - 5$

And by this, in order for us to fully understand that this would be true, the following would enable us to understand.

$\Rightarrow \left[\begin{array}{ccc}A+B) * (A-B) =\\
 A2 - AB + BA - B2 =\\
 A2 - AB + AB - B2 = \\
 A2 - B2\end{array}\right] \Leftarrow$

$\boxed{\bf{ \frac{3*(2k^2-5)*3-(5k)}{3} = \frac{18k^2-5k-45}{3} }}$

$Factoring : 18k^2 - 5k - 45 \\ \\ \left[\begin{array}{ccc} -810 + 1 = -809 \\
 -405 + 2 = -403 \\
 -270 + 3 = -267\\ -162 + 5 = -157 \\
 -135 + 6 = -129 \\
 -90 + 9 = -81 
 
 
\end{array}\right]$

$(Your \ Answer) : \boxed{\boxed{\bf{ \frac{18k^2-5k-45}{3} }}}$

4 0

4 years ago