3 years ago

If (x + 2) is a factor of x3 – 19x – p, find the value of p. Help please

Mathematics

1 answer:

Sergio039 [100]3 years ago

3 0

If $x-a$ is a factor of a polynomial $P(x)$ then, $a$ is its root.

So $-2$ is a root of $x^3-19x-p$

$(-2)^3-19\cdot(-2)-p=0\\-8+38-p=0\\p=30$

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PLEASE HELP ME PLEASE

SCORPION-xisa [38]

<h3>Step-by-step explanation:</h3><h3>(2/3)x - 2 = 7</h3>

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(2/3)x = 9

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Answer:

First odd number = 13

Second odd number = 15

Step-by-step explanation:

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Second odd number = 2x + 3

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So,

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Second odd number = 2x + 3= 2*6 +3= 12 + 3 = 15

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If (x + 2) is a factor of x3 – 19x – p, find the value of p. Help please​

If (x + 2) is a factor of x3 – 19x – p, find the value of p. Help please