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3 years ago

Help, please?? ^ω^ xx

Mathematics

1 answer:

Rudiy273 years ago

7 0

Step 1. Use Multiplication Distributive Property
4*3^3(x^2)^3(y^4)^3
Step 2. Simplify 3^3 to 27
4*27(x^2)^3(y^4)^3
Step 3. Use the Power Rule
4*27x^6(y^4)^3
Step 4. Use the Power Rule
4*27x^6y^12
Step 5. Simplify.
The answer is 108x^6y^12

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Find the amount in the bank after 7 years if interest is compounded quarterly?

qwelly [4]

Answer:

a) amount in the bank after 7 years if interest is compounded quarterly is $6,605

b) amount in the bank after 7 years if interest is compounded quarterly is $6,612.57

Step-by-step explanation:

We are given:

Principal Amount P= 5000

Rate r= 4% = 0.04

time t = 7 years

The formula used is: $A=P(1+\frac{r}{n})^{nt}$

where A is future value, P is principal amount, r is rate, n is compounded value and t is time

a) Find the amount in the bank after 7 years if interest is compounded quarterly?

If interest is compounded quarterly then n = 4

Using values given in question and finding A

$A=P(1+\frac{r}{n})^{nt}\\A=5000(1+\frac{0.04}{4})^{4*7} \\A=5000(1+0.01)^{28}\\A=5000(1.01)^{28}\\A=5000(1.321)\\A=6,605$

So, amount in the bank after 7 years if interest is compounded quarterly is $6,605

b) Find the amount in the bank after 7 years if interest is compounded monthly?

If interest is compounded quarterly then n = 12

Using values given in question and finding A

$A=P(1+\frac{r}{n})^{nt}\\A=5000(1+\frac{0.04}{12})^{12*7} \\A=5000(1+0.003)^{84}\\A=5000(1.003)^{84}\\A=5000(1.322)\\A=6,612.57$

So, amount in the bank after 7 years if interest is compounded quarterly is $6,612.57

6 0

3 years ago

What is the area of 38cm and 47cm help please

FinnZ [79.3K]

Answer:

1786

Step-by-step explanation:

Area of a rectangle = l x b

= 38 x 47

= 1786

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3 years ago

HELPP!!! Need answer as soon as possible.

posledela

Answer:

Option C. The open and closed circles are reversed and the graph shifts up.

Step-by-step explanation:

From the graph of the functions (Attached below) you can check that for the interval 0 ≤x<1 the floor function takes the value 0 everywhere, also it has closed brackets at 0 and open brackets at 1.

On the other hand for the interval 0<x≤1 the ceiling function takes the value 1, also it has open brackets at 0 and closed brackets at 1.

For that reason we conclude that the open and closed circles are reversed and the graph shifts up.

5 0

4 years ago