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Oxana [17]
3 years ago
5

Anyone wanna play Bloons tower defense 5 im rank 52

Computers and Technology
2 answers:
diamong [38]3 years ago
8 0

Answer:

nah im good fam thanks for askin

Explanation:

yarga [219]3 years ago
7 0

I would like too but i do not have the game

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Write a program whose input is a string which contains a character and a phrase, and whose output indicates the number of times
otez555 [7]

Answer:

The program written in python is as follows

def countchr(phrase, char):

     count = 0

     for i in range(len(phrase)):

           if phrase[i] == char:

                 count = count + 1

     return count

phrase = input("Enter a Phrase: ")

char = input("Enter a character: ")

print("Occurence: ",countchr(phrase,char))

Explanation:

To answer this question, I made use of function

This line defines function countchr

def countchr(phrase, char):

This line initializes count to 0

     count = 0

This line iterates through each character of input phrase

     for i in range(len(phrase)):

This line checks if current character equals input character

           if phrase[i] == char:

The count variable is incremented, if the above condition is true

                 count = count + 1

The total number of occurrence is returned using this line

     return count

The main method starts here; This line prompts user for phrase

phrase = input("Enter a Phrase: ")

This line prompts user for a character

char = input("Enter a character: ")

This line prints the number of occurrence of the input charcater in the input phrase

print("Occurence: ",countchr(phrase,char))

4 0
3 years ago
In this exercise you will debug the code which has been provided in the starter file. The code is intended to do the following:
abruzzese [7]

Answer:

The corrected code is as follows:

import java.util.Scanner;

public class U2_L4_Activity_Two{

public static void main(String[] args){

Scanner scan = new Scanner(System.in);

String str1 = scan.nextLine();

String str2 = str1;

str1 = str1.toUpperCase();

System.out.println(str1);

System.out.println(str2);

}

}

Explanation:

This corrects the scanner object

Scanner scan = new Scanner(System.in);

This line is correct

String str1 = scan.nextLine();

This copies str1 to str2

String str2 = str1;

This converts str1 to upper case

str1 = str1.toUpperCase();

This prints str1

System.out.println(str1);

This prints str2

System.out.println(str2);

8 0
3 years ago
Explain about forensic tools?
Ganezh [65]

Answer:

 In the computer forensics, it basically examining the digital media by using the different types of specialist tools which is known as forensic tool.

It has the ability to acquiring the several evidence from the computer hard disk and by copying information, the data from the machine that can be procured and after that broke down for any data that is appropriate for the case.

There are different types of forensics tools that are:

  • SIFT (SANS Investigative Forensics Toolkit)
  • Volatility
  • Redline
  • Digitally forensics framework
  • COFEE

4 0
3 years ago
Which principle or element of layout design is highlighted in this event poster?
Oduvanchick [21]

The  principle or element of layout design is highlighted in an event poster in option i: The headline.

<h3>What are the elements of page layout?</h3>

The poster is known to be one that often uses a kind of hierarchy and centered text alignment as its element.

Note that it is one whose Lines of use is said to be made up of different kinds of type styles, sizes and others.

The simple elements of an advertising poster is made up of:

1. The headline.

2. The sub-head.

3. The body copy.

4. The caption.

The elements of page layout are visual hierarchy, visual flow, and others. Hence, the  principle or element of layout design is highlighted in an event poster in option i: The headline.

Learn more about layout design from

brainly.com/question/2501083

#SPJ1

6 0
2 years ago
Write a function that checks whether two words are anagrams. Two words are anagrams if they contain the same letters. For exampl
Masteriza [31]

Answer:

def isAnagram(s1, s2):

   list1=s1

   list2=s2

   sortedlist1 = sorted(list1)

   sortedlist2 = sorted(list2)

   if sortedlist1 == sortedlist2:

       print(list1+ " and "+list2+ " are anagram")

   else:

       print(list1+ " and "+list2+ " are not anagram")

Explanation:

Here is a call to the function isAnagram():

list1 =input("Enter String1 ")

list1 =input("Enter String2 ")

isAnagram(list1,list2)

Attached is the run and output for this program

4 0
3 years ago
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