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3 years ago

The answer to this question?

Mathematics

1 answer:

makkiz [27]3 years ago

4 0

Answer:

80000 metres

Step-by-step explanation:

The scale i'm assuming is 1 cm : 20000 m

Multiply 4 (for you are solving for 4 cm) to both sides of the ratio:

1(4) : 20000(4)

4 : 80000

80000 metres is the actual distance when the map shows 4 cm.

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Find the derivative of f(x) = 4x + 7 at x = 5. 4 1 5 7

Andrej [43]

For this case we have the following function:
$f(x) = 4x + 7 
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Deriving the function we have:
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We now evaluate the function for the value of x = 5.
We have then:
$f '(5) = 4 
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Answer:
the derivative of f(x) = 4x + 7 at x = 5 is:
4

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3 years ago

If an odd number is less than 15, then it is prime

ruslelena [56]

Answer:

False

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3 years ago

<img src="https://tex.z-dn.net/?f=%20%5Cint%5Climits%5E5_1%20%7B%20%5Cfrac%7BlnR%7D%7B%20R%5E%7B2%7D%20%20%7D%20%5C%2C%20dR%20"

alex41 [277]

Integrate by parts, setting

$\begin{matrix}u=\ln R&&\mathrm dv=\dfrac{\mathrm dR}{R^2}\\\mathrm du=\dfrac{\mathrm dR}R&&v=-\dfrac1R\end{matrix}$

So the integral is

$\displaystyle\int_1^5\frac{\ln R}{R^2}\,\mathrm dR=-\dfrac{\ln R}R\bigg|_{R=1}^{R=5}+\int_1^5\frac{\mathrm dR}{R^2}$
$\displaystyle\int_1^5\frac{\ln R}{R^2}\,\mathrm dR=-\left(\frac{\ln5}5-\frac{\ln1}1)-\frac1R\bigg|_{R=1}^{R=5}$
$\displaystyle\int_1^5\frac{\ln R}{R^2}\,\mathrm dR=-\frac{\ln5}5-\left(\frac15-1\right)$
$\displaystyle\int_1^5\frac{\ln R}{R^2}\,\mathrm dR=\frac15(4-\ln5)$

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4 years ago