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iogann1982 [59]
3 years ago
8

Captain Ishaan has a ship, the H.M.S. Khan. The ship is two furlongs from the dread pirate Luis and his merciless band of thieve

s. The Captain has probability \dfrac{4}{5} 5 4 ​ start fraction, 4, divided by, 5, end fraction of hitting the pirate ship. The pirate only has one good eye, so he hits the Captain's ship with probability \dfrac{1}{7} 7 1 ​ start fraction, 1, divided by, 7, end fraction. If both fire their cannons at the same time, what is the probability that both the pirate and the Captain hit each other's ships?
Mathematics
1 answer:
Sidana [21]3 years ago
3 0

Answer: \frac{4}{35}

Step-by-step explanation: The probability of Captain Ishaan hitting the pirate's ship is:

P(A) = \frac{4}{5}

The probability of the pirate hitting Captain's ship is:

P(B) = \frac{1}{7}

So, the probability of both hitting each other is a probability of A and B occuring, which means:

P(A) . P(B) = \frac{4}{5} . \frac{1}{7}

P(A) . P(B) = \frac{4}{35}

The probability of both the pirate and the Captain hit each other's ship is

\frac{4}{35} or 11.43%

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Solution of this equation
lara31 [8.8K]
2.5y + 3x = 27
5x - 2.5y = 5

Align the variables to make solving this easier.

2.5y + 3x = 27
-2.5y + 5x = 5

You can see that the 2.5y and -2.5y cancel each other out. Then add the 3x and 5x, and 27 + 5.

3x = 27
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Divide both sides by 8.

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Now input that x into one of the equations to get y. 

2.5y + 3(4) = 27
2.5y + 12 = 27
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The answer to this system of equations is x = 4, y = 6. (4, 6)
5 0
3 years ago
What is b?<br> 6/8 = 21/b
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Answer:

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The answer would be about 8/12 because you must convert 4/6 into 8/12. 8/12 + 3/12=11/12 
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