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user100 [1]
3 years ago
7

A sequence can be generated by using an = a(n-1) + 3, where ai = 8 and n is a whole number greater than 1. What are the first fo

ur terms in the sequence? F 8, 16, 24, 32 G 3, 6, 9, 12 H 3, 11, 19, 27 3 8, 11, 14, 17​ I need answers ASAP

Mathematics
1 answer:
Georgia [21]3 years ago
3 0

Answer:

J

Step-by-step explanation:

a1=8 (as given)

a2=a1+3=8+3=11

a3=a2+3=11+3=14

a4=a3+3=14+3=17

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Natalka [10]
44ft I hope this helped
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3 years ago
Can someone please help me with decimal points as they are my weakness
kramer
For section 1.....Problem a is 7.2 Problem B is 7.6 Problem C is 18.8 Problem E is 32.5 Problem F is 28.8 Problem G is 10 Problem I is 61.5 Problem J is 170.8 Problem K is 81.6. 
For Section 2 Problem A is 9.36 Problem B is 10.35 Problem C is 25.85 Problem E is 1.82 Problem F is 3.28 Problem G is 2.8 Problem I is 42.21 Problem J is 56.16 Problem K is 7.65
5 0
3 years ago
Read 2 more answers
4 divided by what = 9
vfiekz [6]
It 36 hope i helped!!


Assume answer as x;

x÷4=9 or x4=9

Multiply 9 with 4;

x=9×4

x=36

3 0
3 years ago
Read 2 more answers
The diameters of ball bearings are distributed normally. The mean diameter is 106 millimeters and the standard deviation is 4 mi
Assoli18 [71]

Answer:

Probability that the diameter of a selected bearing is greater than 111 millimeters is 0.1056.

Step-by-step explanation:

We are given that the diameters of ball bearings are distributed normally. The mean diameter is 106 millimeters and the standard deviation is 4 millimeters.

<em>Firstly, Let X = diameters of ball bearings</em>

The z score probability distribution for is given by;

          Z = \frac{ X - \mu}{\sigma} ~ N(0,1)

where, \mu = mean diameter = 106 millimeters

            \sigma = standard deviation = 4 millimeter

Probability that the diameter of a selected bearing is greater than 111 millimeters is given by = P(X > 111 millimeters)

    P(X > 111) = P( \frac{ X - \mu}{\sigma} > \frac{111-106}{4} ) = P(Z > 1.25) = 1 - P(Z \leq 1.25)

                                                  = 1 - 0.89435 = 0.1056

Therefore, probability that the diameter of a selected bearing is greater than 111 millimeters is 0.1056.

4 0
3 years ago
I"m actually begging you to help
Rufina [12.5K]

Answer:

(Square, Right Triangle)

18 meters²

Step-by-step explanation:

You can divide the shape into a square and right triangle, see the attachment :)

The area of the square is the length times the width. So,

3 · 3 = 9

The area of the square is 9 m².

The triangle's area is the base times the height divided by 2. So,

6 · 3 = 18

18 / 2 = 9

The triangle has an area of 9 m².

Add these together.

9 + 9 = 18

The area is 18 meters².

6 0
3 years ago
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