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notka56 [123]
3 years ago
15

What is the measure of Angle N M R?

Mathematics
2 answers:
hichkok12 [17]3 years ago
7 0

Answer:

The correct answer is 63.

Step-by-step explanation:

irga5000 [103]3 years ago
5 0

Answer:

63

I took the test!

Step-by-step explanation:

hope this helps. :D

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Determine the standard form of the equation of the line that passes through ( -5,0 ) ( 0 ,-9)
insens350 [35]

The general form for a line through two points (a,b) and (c,d) is

(c-a)(y-b)=(d-b)(x-a)

This is better than the slope forms because it works in the no slope case, as does the standard form.

If you haven't seen it before, it works because when (x,y)=(a,b) we get (c-a)(b-b)=(d-b)(a-a), both sides zero, and when (x,y)=(c,d) we get (c-a)(d-b)=(d-b)(c-a), clearly equal sides.

Here we have

(0 - -5)(y - 0) = (-9 - 0)(x - - 5)

5y = -9(x+5)

5y = -9x - 45

9x + 5y = -45

Ironically there are two standards for standard form; one with the constant alone on the right and one with the whole thing equal to zero.  I like the constant alone.

Answer: 9x + 5y = -45

Check:

We check each point is on the line

(-5,0)

9(-5) + 5(0) = -45, good

(0, -9)

9(0) + 5(-9) = -45, good again


5 0
3 years ago
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The wool sold 4038 tickets to their soccer game the leopard sold 6224 tickets to their game how many more tickets did the leopar
andrew11 [14]
Leopard sold 2186 more tickets than the wolf

5 0
3 years ago
N 25 hour, Matt can type 45 page. <br><br> What is Matt's rate in pages per hour?
Kryger [21]
You can divide 45 by by 25 to get the pages per hour and it’s 1.8
5 0
3 years ago
How do i understand Vertices because i forget sometimes?
Burka [1]
<span>the highest point; the top or apex.<span>
<span>"a line drawn from the vertex of the figure to the base"

</span></span>GEOMETRYeach angular point of a polygon, polyhedron, or other figure.</span>
6 0
3 years ago
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1) Use power series to find the series solution to the differential equation y'+2y = 0 PLEASE SHOW ALL YOUR WORK, OR RISK LOSING
iogann1982 [59]

If

y=\displaystyle\sum_{n=0}^\infty a_nx^n

then

y'=\displaystyle\sum_{n=1}^\infty na_nx^{n-1}=\sum_{n=0}^\infty(n+1)a_{n+1}x^n

The ODE in terms of these series is

\displaystyle\sum_{n=0}^\infty(n+1)a_{n+1}x^n+2\sum_{n=0}^\infty a_nx^n=0

\displaystyle\sum_{n=0}^\infty\bigg(a_{n+1}+2a_n\bigg)x^n=0

\implies\begin{cases}a_0=y(0)\\(n+1)a_{n+1}=-2a_n&\text{for }n\ge0\end{cases}

We can solve the recurrence exactly by substitution:

a_{n+1}=-\dfrac2{n+1}a_n=\dfrac{2^2}{(n+1)n}a_{n-1}=-\dfrac{2^3}{(n+1)n(n-1)}a_{n-2}=\cdots=\dfrac{(-2)^{n+1}}{(n+1)!}a_0

\implies a_n=\dfrac{(-2)^n}{n!}a_0

So the ODE has solution

y(x)=\displaystyle a_0\sum_{n=0}^\infty\frac{(-2x)^n}{n!}

which you may recognize as the power series of the exponential function. Then

\boxed{y(x)=a_0e^{-2x}}

7 0
3 years ago
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