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FrozenT [24]
3 years ago
11

Income Suppose income from an endowment is generated at the annual rate of $42,000 per year. Find the capital value of this endo

wment at an interest rate of 7.5% compounded continuously.
Mathematics
1 answer:
Mrac [35]3 years ago
4 0

Answer:

Capital value after 1 year will be equal to $45150

Step-by-step explanation:

We have given principal amount P = $42000

Rate of interest r = 7.5 %

Time t = 1 year

Capital value is given by A=P(1+\frac{r}{100})^n

So A=42000\times (1+\frac{7.5}{100})^1

A=42000\times 1.075=45150

So capital value after 1 year will be equal to $45150

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Ok, but where is the table???
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Solve the equation. x + 2.6 = 3.5<br>    x = –0.9 <br>   x = –6.1 <br>   x = 6.1<br>    x = 0
denpristay [2]

x + 2.6 = 3.5\\ \\ x=3.5-2.6\\ \\ x=0.9

There may be an error with the first answer choice because it can't have a negative. The problem is x + 2.6 = 3.5 correct?

Hope this helps!

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Jarron has a piece of chalk tied to the end of a
solniwko [45]

Answer: A 24 cm piece of string is cut into two pieces , one piece is used to form a circle and the other piece is used to form a square.

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then

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Find the area of the circle

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r =  

Find the area of the circle

A =  

A =  

A =  sq/cm, the area of the circle

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Find the area of the square

A =  sq/cm the area of the square

The total area

At =  +  

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Step-by-step explanation: Hope I help out alot (-: :-)

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Help me please, guys <br>​
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Answer:

7.7

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3 0
3 years ago
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A business school has a goal that the average number of years of work experience of its MBA applicants is more than three years.
gizmo_the_mogwai [7]

Answer:

z=\frac{3.1-3}{\frac{2.449}{\sqrt{47}}}=0.280    

p_v =P(z>0.280)=0.390  

If we compare the p value and the significance level assumed \alpha=0.01 we see that p_v>\alpha so we can conclude that we have enough evidence to fail reject the null hypothesis, so we can't conclude that the height of men actually its NOT significant higher than 0.3 at 1% of signficance.  

Step-by-step explanation:

Data given and notation  

\bar X=3.1 represent the sample mean

\sigma=\sqrt{6} represent the sample standard deviation for the sample

n=47 sample size  

\mu_o =3 represent the value that we want to test

\alpha represent the significance level for the hypothesis test.  

t would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the mean is higher than 3, the system of hypothesis would be:  

Null hypothesis:\mu \leq 3  

Alternative hypothesis:\mu > 3  

If we analyze the size for the sample is > 30 and we know the population deviation so is better apply a z test to compare the actual mean to the reference value, and the statistic is given by:  

z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}}  (1)  

z-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

Calculate the statistic

We can replace in formula (1) the info given like this:  

z=\frac{3.1-3}{\frac{2.449}{\sqrt{47}}}=0.280    

P-value

Since is a one side test the p value would be:  

p_v =P(z>0.280)=0.390  

Conclusion  

If we compare the p value and the significance level assumed \alpha=0.01 we see that p_v>\alpha so we can conclude that we have enough evidence to fail reject the null hypothesis, so we can't conclude that the height of men actually its NOT significant higher than 0.3 at 1% of signficance.  

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3 years ago
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