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kirill115 [55]
4 years ago
10

Elsa plans to save $4 each week from her allowance. Elsa's Cousin Sara had seven dollars saved from her birthday and also plans

on saving an additional $4 each week from her allowance. After one year, how much will each cousin have saved?
Mathematics
1 answer:
Licemer1 [7]4 years ago
8 0

Answer:

sara will have 215.00. Sara already had 7.00 saved. 208 + 7= 215.00

Elsa will 208 dollars

Step-by-step explanation:

52 weeks in a year.

52x4 = 208

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Evaluate −12(−2). (1 point) 14 −14 −24 24
masya89 [10]

Answer:

24.

Step-by-step explanation:

−12(−2

= -12 * -2     ( Note  - * - = +) so we have:

24 (answer).

6 0
4 years ago
-x + 4y = -4<br> y = 1/2x -2
anygoal [31]
<h2>(x, y) = (6, 1)</h2>

Step-by-step explanation:

-x + 4y = -4

y = 1/2x -2

-x + 4(1/2x - 2) = -4

-x + 2x - 2 = 4

x = 4 + 2

x = 6

y = 1/2x - 2

y = 1/2 x 6 - 2

y = 3 - 2

y = 1

(x, y) = (6, 1)

3 0
3 years ago
Describe how you could draw a diagram for a problem finding the total length for two strings, 15 inches long and 7 inches long
Tema [17]
Pay attention in class
6 0
3 years ago
The solution is incorrect. HIGHLIGHT the step that does not follow logically from the previous step. Explain why it is incorrect
Naya [18.7K]
It’s wrong because you put the x and the 3 in parentheses when it’s wrong there
8 0
3 years ago
Which expression is equivalent to (5g^4+5g^3-17g^2+6g)-(3g^4+6g^3-7g^2-12)/g+2
ankoles [38]

Option C:

2 g^{3}-5 g^{2}+6

Solution:

Given expression:

$\frac{\left(5 g^{4}+5 g^{3}-17 g^{2}+6 g\right)-\left(3 g^{4}+6 g^{3}-7 g^{2}-12\right)}{g+2}

To find which expression is equal to the given expression.

$\frac{\left(5 g^{4}+5 g^{3}-17 g^{2}+6 g\right)-\left(3 g^{4}+6 g^{3}-7 g^{2}-12\right)}{g+2}

Expand the term -\left(3 g^{4}+6 g^{3}-7 g^{2}-12\right):-3 g^{4}-6 g^{3}+7 g^{2}+12

         $=\frac{5 g^{4}+5 g^{3}-17 g^{2}+6 g- 3 g^{4}-6 g^{3}+7 g^{2}+12}{g+2}

Arrange the like terms together.

         $=\frac{5 g^{4}- 3 g^{4}+5 g^{3}-6 g^{3}-17 g^{2}+7 g^{2}+6 g+12}{g+2}

         $=\frac{2 g^{4}- g^{3}-10 g^{2}+6 g+12}{g+2}

Factor the numerator 2 g^{4}-g^{3}-10 g^{2}+6 g+12=(g+2)\left(2 g^{3}-5 g^{2}+6\right)

         $=\frac{(g+2)\left(2 g^{3}-5 g^{2}+6\right)}{g+2}

Cancel the common factor g + 2, we get

         =2 g^{3}-5 g^{2}+6

Hence option C is the correct answer.

8 0
3 years ago
Read 2 more answers
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