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zhannawk [14.2K]
4 years ago
11

What is the approximate volume of the cylinder? Use 3.14 for п.

Mathematics
1 answer:
Veseljchak [2.6K]4 years ago
4 0

<u>Given</u>:

Given that the radius of the cylinder is 4 cm.

The height of the cylinder is 9 cm.

We need to determine the volume of the cylinder.

<u>Volume of the cylinder:</u>

The volume of the cylinder can be determined using the formula,

V=\pi r^2 h

where r is the radius and h is the height of the cylinder.

Substituting π = 3.14, r = 4 and h = 9 in the above formula, we get;

V=(3.14)(4)^2(9)

V=(3.14)(16)(9)

V=452.16 \ cm^3

Thus, the volume of the cylinder is 452.16 cm³

Hence, Option B is the correct answer.

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A horizontal trough is 16 m long, and its end are isosceles trapezoids with an altitude of 4 m, a lower base of 4 m, and an uppe
Ganezh [65]

Answer:

0.28cm/min

Step-by-step explanation:

Given the horizontal trough whose ends are isosceles trapezoid  

Volume of the Trough =Base Area X Height

=Area of the Trapezoid X Height of the Trough (H)

The length of the base of the trough is constant but as water leaves the trough, the length of the top of the trough at any height h is 4+2x (See the Diagram)

The Volume of water in the trough at any time

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We are not given a value for x, however we can express x in terms of h from Figure 3 using Similar Triangles

x/h=1/4

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x=h/4

Substituting x=h/4 into the Volume, V

V=64h+16h(\frac{h}{4})

V=64h+4h^2\\\frac{dV}{dt}= 64\frac{dh}{dt}+8h \frac{dh}{dt}

h=3m,

dV/dt=25cm/min=0.25 m/min

0.25= (64+8*3) \frac{dh}{dt}\\0.25=88\frac{dh}{dt}\\\frac{dh}{dt}=\frac{0.25}{88}

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The rate is the water being drawn from the trough is 0.28cm/min.

3 0
4 years ago
A swimming pool measures 35 feet wide by 50 feet long. What is the ratio of the length to the perimeter in simplest form? Perime
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So, let’s find out the numbers needed to form the ratio. The length of the swimming pool is 50 ft long. We need to find the perimeter. 2(50+35)
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3 years ago
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