All categories

3 years ago

A wise man once said, “500 reduced by 4 times my age is 256.” What is his age

Mathematics

2 answers:

RUDIKE [14]3 years ago

6 0

Answer:

His age = 61 years

Step-by-step explanation:

Let us consider my age is x

500 - 4 x = 256

500 - 256 = 4 x

i.e 4 x = 500 - 256

4 x = 244

∴ x = $\frac{244}{4}$

x = 61

His age = 61 years

ch4aika [34]3 years ago

5 0

The answer to this question is 2.048

You might be interested in

Please Help!! Solve x2 = 121. A. 60.5 B. −11 C. 11 D. ±11

torisob [31]

D is the right answer

8 0

3 years ago

Read 2 more answers

Walker is reading a book that is 792 pages. He reads 15 pages a day during the week, and 25 pages a day during the weekend. Afte

liubo4ka [24]

Answer:

167 Pages Left To Read

Step-by-step explanation:

15*5=75

75*5=375

375+ 25*10=625

792-625=167

8 0

3 years ago

Determine the domain of the function (fog) (x) where f(x) = 3x-1/x-4 and g(x)=x+1/x

Mrac [35]

Answer:

$(-\infty,0)\cup(0, \frac{1}{3})\cup (\frac{1}{3},\infty)$

Step-by-step explanation:

The given functions are $f(x)=\frac{3x-1}{x-4}$ and $g(x)=\frac{x+1}{x}$ .

We now composed the two functions to find:

$(f\circ g)(x)=f(g(x))$

$\implies (f\circ g)(x)=f(\frac{x+1}{x})$

$\implies (f\circ g)(x)=\frac{3(\frac{x+1}{x})+1}{\frac{x+1}{x}-4}$

$\implies (f\circ g)(x)=\frac{4x+3}{1-3x}$

This function is defined if the denominator is not zero.

$1-3x\ne0$

$x\ne\frac{1}{3}$

We write this in interval notation as:

$(-\infty,\frac{1}{3})\cup (\frac{1}{3},\infty)$

We need to be cautious here as x=0 is not in the domain of g(x).

Therefore the domain of $(f\circ g)(x)$ is

$(-\infty,0)\cup(0, \frac{1}{3})\cup (\frac{1}{3},\infty)$

4 0

3 years ago

3927283+8093 Help pls

Debora [2.8K]

Answer: 3935376

Step-by-step explanation: 3927283+8093

3935376

7 0

2 years ago

Read 2 more answers

5. Which picture shows a rotation of the flag? (1) (2) (3) (4)

RUDIKE [14]

Answer:

4 my good sir

Step-by-step explanation:

4 0

3 years ago