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IrinaK [193]
3 years ago
15

A point having a negative abscissa and negative ordinate is in quadrant ____.

Mathematics
2 answers:
m_a_m_a [10]3 years ago
8 0
The ordered pair is (abscissa,ordinate).
Take note that
Quadrant I = (+,+)
Quadrant II = (-,+)
Quadrant III = (-,-)  (ANSWER)
Quadrant IV = (+,-)

Aloiza [94]3 years ago
5 0
Your answer would be Quadrant III (Answer #3)

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Consider △RST and △RYX.
astra-53 [7]

Answer:

B. StartFraction R Y Over R S EndFraction = StartFraction R X Over R T EndFraction = StartFraction X Y Over T S EndFraction

i.e \frac{RY}{RS} = \frac{RX}{RT} = \frac{XY}{TS}

Step-by-step explanation:

Two or more shape or figures are similar when their sides and angles can be compared appropriately.

In the given figure, ΔRXY is within ΔRST. Since the two triangles are similar, then their length of sides can be compared in the form of required ratios.

So that by comparison,

\frac{RY}{RS} = \frac{RX}{RT} = \frac{XY}{TS}

Therefore, the correct option to the question is B.

8 0
2 years ago
Read 2 more answers
Help!!! Assignment due in 20 minutes!!
Vitek1552 [10]

Answer:

2

Step-by-step explanation:

The answer would be 2 because it reduces to the same system of equations as the original, which I knew since the first equation was the same and if you divide everything in the second by 2, you'll get 3x-y=8. :)

7 0
3 years ago
The vertices of triangle JKL, shown below, are J(2, 1), K(4, 4), and L(6, 2). If triangle JKL is translated 2 units to the left
julia-pushkina [17]

Answer:

L=(4,-2)

Step-by-step explanation:Left = -2 units and down = -4 units, left is x direction and down is y direction. (x,y).

8 0
2 years ago
The American Management Association is studying the income of store managers in the retail industry. A random sample of 49 manag
VashaNatasha [74]

Answer:

a) The 95% confidence interval for the income of store managers in the retail industry is ($44,846, $45,994), having a margin of error of $574.

b) The interval mean that we are 95% sure that the true mean income of all store managers in the retail industry is between $44,846 and $45,994.

Step-by-step explanation:

Question a:

We have to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1 - 0.95}{2} = 0.025

Now, we have to find z in the Z-table as such z has a p-value of 1 - \alpha.

That is z with a p-value of 1 - 0.025 = 0.975, so Z = 1.96.

Now, find the margin of error M as such

M = z\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample.

M = 1.96\frac{2050}{\sqrt{49}} = 574

The lower end of the interval is the sample mean subtracted by M. So it is 45420 - 574 = $44,846.

The upper end of the interval is the sample mean added to M. So it is 45420 + 574 = $45,994.

The 95% confidence interval for the income of store managers in the retail industry is ($44,846, $45,994), having a margin of error of $574.

Question b:

The interval mean that we are 95% sure that the true mean income of all store managers in the retail industry is between $44,846 and $45,994.

5 0
2 years ago
Can I please please get help with this?
Hatshy [7]

Answer:

the answer is 42

84÷2

42

4 0
3 years ago
Read 2 more answers
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