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serg [7]
3 years ago
8

Can anyone help me with this?

Mathematics
1 answer:
aleksklad [387]3 years ago
8 0
With the given table, this isn't possible without resorting to an approximation of an approximation.

The interval [0,8] can be partitioned as [0,2]\cup[2,4]\cup[4,6]\cup[6,8], with the respective midpoints of t\in\{1,3,5,7\}. So the average temperature is given exactly by the definite integral

\displaystyle\frac1{8-0}\int_0^8f(t)\,\mathrm dt

which is approximated by

\displaystyle\frac14\sum_{t\in\{1,3,5,7\}}f(t)=\dfrac{f(1)+f(3)+f(5)+f(7)}4

where the coefficient \dfrac14 comes from the fact that each subinterval has length 2, and so \dfrac28=\dfrac14.

However, you don't know the values of f(t) at these points. At best you can approximate them, perhaps by interpolating f(t) (you have the details needed to do it, at any rate).

Are you sure you're not supposed to find the average temperature over the entire set of observation times, i.e. over 0\le t\le16?
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Using relations in a right triangle, it is found that:

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<h3>What are the relations in a right triangle?</h3>

The relations in a right triangle are given as follows:

  • The sine of an angle is given by the length of the opposite side to the angle divided by the length of the hypotenuse.
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In this triangle:

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Hence the tangent of A is:

tan(A) = 30/40 = 3/4 = 0.75.

More can be learned about relations in a right triangle at brainly.com/question/26396675

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