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valentinak56 [21]
3 years ago
6

How do you do this anyone know how

Mathematics
1 answer:
IceJOKER [234]3 years ago
5 0
Slope is rise over run, or the change in y over the change in x. So, you go up vertically then directly horizontal and whatever the change is is the slope.

For example, the first one is -1/3. It's slope is going down to the right, so it's negative . It goes down 1 (y value) and over to the right 3 (x value). Since it goes down and to the right it is a slope of -1/3.
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Answer:

3/2 or 1.5

Step-by-step explanation:

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Find the range and interquartile range for the data represented by the box plot.
Anarel [89]

<u>Given</u>:

Given that the data are represented by the box plot.

We need to determine the range and interquartile range.

<u>Range:</u>

The range of the data is the difference between the highest and the lowest value in the given set of data.

From the box plot, the highest value is 30 and the lowest value is 15.

Thus, the range of the data is given by

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<u>Interquartile range:</u>

The interquartile range is the difference between the ends of the box in the box plot.

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3 0
3 years ago
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Let f(x) be a continuous function such that f(1) and f'(x)-Vx3 + 6. What is the value of,f(5)? (A) 11.446 (C) 24.672 (B) 13.446
tia_tia [17]

Answer:

f(5) = 26.672 which is option D

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From question, f(1) = 2 and f'(x)=√(x^3 + 6)

f(5) = f(1) + (5,1)∫ f'(x) dx

Integrating using the boundary 5 and 1;

f(5) = 2 + (5,1)∫√(x^3 + 6) dx

f(5) = 2 + 24.672

So f(5) = 26.672

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Simplify:<br> -11√21-11√/21
alex41 [277]

Step-by-step explanation:

by using the radical and suds rule

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