The answer to your question is A
Answer:
x=-3
|-x| = 3
|x| = 3
Step-by-step explanation:
we know that
If a number is a solution of a equation, then the number must satisfy the equation
<em>Verify each case</em>
case 1) we have
x=3
substitute the value of x=-3
-3=3 -----> is not true
therefore
x=-3 is not a solution of the given equation
case 2) we have
x=-3
substitute the value of x=-3
-3=-3 -----> is true
therefore
x=-3 is a solution of the given equation
case 3) we have
|-x| = 3
substitute the value of x=-3
|-(-3)| = 3
|3| = 3
3=3-----> is true
therefore
x=-3 is a solution of the given equation
case 4) we have
|x| = 3
substitute the value of x=-3
|(-3)| = 3
3=3-----> is true
therefore
x=-3 is a solution of the given equation
case 5) we have
-|x| = 3
substitute the value of x=-3
-|(-3)| = 3
-3=3-----> is not true
therefore
x=-3 is not a solution of the given equation
Hello Nozohonoumi,
Answer:
Price: $ 57.00
Sales Tax (2%): $ 1.14
Total: $ 58.14
Answer: i hope i helped if not im truly sorry
Solving for 9x^2 - 25 = 0
Standard form:
9x2 − 25 = 0
Solutions based on quadratic formula:
x1
= −0 − √ 02 − 4×9×(−25)
2×9
= 0 − 30 × √ 1
18
≈ −1.667
x2
= −0 + √ 02 − 4×9×(−25)
2×9
= 0 + 30 × √ 1
18
≈ 1.667
Extrema:
Min = (0, −25)
Step-by-step explanation: im not dumb and im not smart
Answer:
y = 1
x = -2
Step-by-step explanation:
During the substitution method, you are substituting one function into another. Because both functions are set equal to "x", you can make the functions equal each other. This allows you to 'get rid' of the "x" variable and simplify to find the value of "y".
5A) x = -2y
5B) x = 2 - 4y
-2y = 2 - 4y <----- Set both equations equal
2y = 2 <----- Add 4y to both sides
y = 1 <----- Divide both sides by 2
Now that you know what "y" equals, you can plug that value into the "y" variable into one of the equations. This will allow you to then simplify and find the answer for "x".
x = -2y <----- Equation 5A
x = -2(1) <----- Plug 1 into "y"
x = -2 <----- Multiply -2 and 1
