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balandron [24]
4 years ago
5

Subtract -b + 3 from -11b - 4 10b - 7 -10b -7 10b + 7 -12b - 1

Mathematics
1 answer:
Andreas93 [3]4 years ago
6 0
-11b-4-(-b+3)
goes to -11b-4+b-3
=-10b-7
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How do you write 32,05,008 in expand form and word form
Hunter-Best [27]
3,205,008 = 3,000,000 + 200,000 + 5,000 + 8 in expanded form
3,205,008 = 3 million, 2 hundred and five thousand and eight in word form.
3 0
3 years ago
The sum of the ages of three brothers Tema,Juma and Abdul is 65 years. Juma is twice as old as Abdul and a half times as old as
Ber [7]

Answer:

Tema = 26 years

Juma = 13 years

Abdul = 26 years

Step-by-step explanation:

Let their ages be represented as:

Tema = x

Juma = y

Abdul = z

From the question, we are told that:

Juma is twice as old as Abdul

y = 2z

z = y/2

= 0.5y

And Juma is a half times as old as Tema.

y = 1/2x

y = 0.5x

x = y/0.5

x = 2y

Hence,

x + y + z = 65

2y + y + 2y = 65

= 5y = 65

y = 65/5

y = 13 years

Since y = Zuma's age, Zuma is 13 years old

From the above question

Since 2y = z

y = 13

2 × 13 = z

z = 26

Since z = Abdul's age, Abdul is 26 years old

From the above question

x = 2y

y = 13 years

x = 2 × 13 years

x = 26 years.

Since x = Tema's age

Tema is 26 years.

Therefore, their present ages are:

Tema = 26 years

Juma = 13 years

Abdul = 26 years

7 0
3 years ago
Lisa has a certain amount of money. She spent 39 dollars and has 3/4th of the original amount left. How much money did she have
harina [27]
If \frac { 3 }{ 4 } is left, that means \frac { 1 }{ 4 } was spent. So \frac { 1 }{ 4 } of the total amount is equal to 39.. Let's say x to the total amount. \frac { 1 }{ 4 } \cdot x=39\\ x=4\cdot 39\\ x=156\\

4 0
3 years ago
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What is the net monthly cash flow
Eddi Din [679]

Answer:

what?


Step-by-step explanation:


7 0
3 years ago
Find the 8th term of the geometric sequence, given the first term and common ratio. a1=6 r=-1/3
Damm [24]

The rule of a geometric sequence:

a_n=a_1r^{n-1}

We have:

a_1=6;\ r=-\dfrac{1}{3}

Find a_8=?\to n=8

substitute:

a_8=6\cdot\left(-\dfrac{1}{3}\right)^{8-1}=6\cdot\left(-\dfrac{1}{3}\right)^7=6\cdot\left(-\dfrac{1}{2187}\right)=-\dfrac{2}{729}

8 0
3 years ago
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