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rjkz [21]
4 years ago
15

What is the cost for the problem below

Mathematics
2 answers:
Tpy6a [65]4 years ago
6 0

Answer:

770

Step-by-step explanation:

because if u add 450+320 equal 770 so that your answer

olasank [31]4 years ago
4 0

Answer: it will cost $3190.752

Step-by-step explanation:

Step 1

We would determine the length of the side of the field, AC. To do this, we would apply the cosine rule. Since we know sides AB and BC and angle B, It will be expressed as

b^2 = a^2 + c^2 - 2acCosB. It becomes

b^2 = 320^2 + 450^2 - 2×320×450Cos80

= 102400 + 202500 - 144000Cos80

= 304900 - 24998.4

b^2 = 279901.6

b= √279901.6

b = 529.06 yards

Step 2

We would determine the area of the triangle. The formula for the area of the triangle is expressed as

Area of triangle = 1/2 × acSinB

Area of triangle = 1/2 × 320 × 450 × Sin 80

Area of triangle = 72000 × 0.9848 = 70905.6 yards^2

If 100 square yards cost $4.50

70905.6 square yards cost (70905.6×4.5) /100 = $3190.752

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